911
« on: June 18, 2014, 01:10:27 PM »
I once developed a cipher, it's not so much of a language really.
Blockland = 26x5y3N6x17x4
This stuff be simple.
Here's the cipher:
a = 1
b = 2
c = 3
d = 4
e = 5
f = 6
g = 7
h = 8
i = 9
forgeter's about to get tricky:
j = 5x
k = N
l = 6x
m = W
n = 7x
o = 5y
p = 8x
q = G
r = 9x
s = U
The trickiness envelopes this stuff like a hug from a 850 pound woman:
t = 5xx
u = 7y
v = Kx
w = T
x = 6xx
y = 5E
z = Wx
Here's an explanation:
First I'll explain the little x's and y's
x is a 2
so if I did
6xx or 6•2•2
I would get 24
which would be the letter x in correlation to its placement in the English alphabet.
y is a 3
so if I did
7y or 7•3
I would get 21
which would be the letter n in correlation to its placement in the English alphabet.
So if the number is more than one digit you either divide by 2 or divide by 3. The reason I did that is so we keep everything single digits, so:
j is the 10th letter in the English alphabet, 10 ÷ 2 = 5 therefore 5x = j
The reason for the big letters is simply because the numbers are prime
Heres all the prime numbers/letters and their correct coding:
k = 11 = N
m = 13 = W
q = 17 = G
s = 19 = U
w = 23 = T
There are two complicated ones, y and z
y:
25 ÷ 5 = 5
I decided earlier on that if I came across a number like this I would symbolize E being itself.
Meaning in the code 5E: E = 5
Turned out it only happened once, so what was I gonna do?
z:
26 ÷ 2 = 13 which is prime so 13 is symbolized by W
but you need to multiply by 2 so
you get: 13 • 2 = 26
OR
W • x = z
Bitches can't handle the advanced simple mathematics that are going on in this stuff.