16
Off Topic / Re: Impossible Math
« on: July 29, 2009, 02:14:50 AM »
You sir, are the idiot!
(x+y)(x-y) = y(x-y)
Here is the step where the division occurs. Watch closely!
(x+y)*(x-y) = y*(x-y)
Two parenthesis next to each other or a number/variable next to the parenthesis means multiplication.
(x+y)*(x-y)/(x-y) = y*(x-y)/(x-y)
The same thing is being multiplied on both sides.
To undo this, we have to DIVIDE by the same number on both sides.
(x+y)*(x-y)/(x-y)1 = y*(x-y)/(x-y)1
Oshi! The two operations canceled each other out!
(x+y)*1 = y*1
Anything divided by itself equals one. Just what we wanted because 1 is the identity for multiplication!
Anything times 1 equals itself.
(x+y) = y
Almost there. We can get rid of the parenthesis now because the only operation being done is addition.
x+y = y
OMFG! We just got to the next step of the problem using division!
Too bad it completely destroys the problem because the division just happened to be 0.
Tard
(x+y)(x-y) = y(x-y)
Here is the step where the division occurs. Watch closely!
(x+y)*(x-y) = y*(x-y)
Two parenthesis next to each other or a number/variable next to the parenthesis means multiplication.
(x+y)*(x-y)/(x-y) = y*(x-y)/(x-y)
The same thing is being multiplied on both sides.
To undo this, we have to DIVIDE by the same number on both sides.
(x+y)*
Oshi! The two operations canceled each other out!
(x+y)*1 = y*1
Anything divided by itself equals one. Just what we wanted because 1 is the identity for multiplication!
Anything times 1 equals itself.
(x+y) = y
Almost there. We can get rid of the parenthesis now because the only operation being done is addition.
x+y = y
OMFG! We just got to the next step of the problem using division!
Too bad it completely destroys the problem because the division just happened to be 0.
Tard