Author Topic: Math  (Read 1766 times)

I never got anything below a B+ in math...and I'm currently in Calculus 3 in university. ;/
I haven't made an A in math all year D:

I love most of Mathematics, I just hate Trigonometry.

I love most of Mathematics, I just hate Trigonometry.

triga brothers

Hm, topic starter has yet to make a reply. I'm gonna have trouble seeing if my answer is right or not. ;/

xy+x+y=z

For X:

x(y+1)+y=z
x(y+1)=z-y
x=(z-y)/(y+1)

now for Y:

y(x+1)+x=z
y(x+1)=z-x
y=(z-x)/(x+1)

This is right! :D

It sparked my memory. Thanks.

Also, this problem wasn't given to me, it was just a conceptual problem to help me do some things.

I can't believe I've forgotten how to do these kinds of problems. I used to working with negative radicals and parabolas.

Meh, I missed those days...

I'm tired with doing 3D and polar coordinates stuff.

So, let's say z is 42.

x = (42 - y)/(y + 1)
y = (42 - x)/(x + 1)

xy + x + y = 42

x[(42 - x)/(x + 1)] + x + (42 - x)/(x + 1) = 42

(x2 + x)(42 - x) + x2 + x + 42 - x = 42x + 42

(x2 + x)(42 - x) + x2 = 42x

42x2 - x3 + 42x - x2 + x2 = 42x

42x2 - x3 = 0

x2(42 - x) = 0

So, x = 0 and 42?

Edit:

Wait...

(x2 + x)(42 - x) + x2 = 42x
x(x + 1)(42 - x) + x2 = 42x
x(42x - x2 + 42 - x) + x2 = 42x
42x - x2 + 42 + x + x = 42
-x2 + 44x + 42 = 42
-x2 + 44x = 0
x2 - 44x = 0
x(x - 44) = 0
So, x = 0 and 44? :/

Can someone check my math? I seem to be off today.
« Last Edit: May 06, 2010, 04:53:16 PM by Deathwishez »

-workingout-

So, x = 0 and 42?
if it works in your original equation, then yes.

also where's y?

I substituted y for (42 - x)/(x + 1) to have just 2 variables.

Quote
So, let's say z is 42.

x = (42 - y)/(y + 1)
y = (42 - x)/(x + 1)

xy + x + y = 42

x[(42-x)/(x+1)]+x+(42-x)/(x+1)=42  - Substituted all values of Y with the above

(42x-x^2)/(x+1)+x+(42-x)/(x+1)=42  -  Result of previous; add the fractions together

-(x^2-41x-42)/(x+1)+x=42  -  Simplify; head straight into division of the polynomials.

---Polynomial Division---

-(x-42)+x=42  -  Result of the division; X's cancel out after distributing the negative 1.

42=42  -  The number is the same for both sides, thus re-inserting an equation back into the original does nothing to obtain values of X and Y.


No, you cannot get values for X and Y.



EDIT: I included what happens per step.
« Last Edit: May 06, 2010, 05:01:34 PM by Bleep »

Wait, so there's not an answer?

What about when using other numbers?

Maybe if you are give a value of X or Y, it may be different. But since you're using the SAME EXACT EQUATION placed into the original, it will cancel everything out.

EDIT: Also, with my edit, you will find out that the equation is an Even function since the end result is the same for both sides. (Or did I get that wrong? Been a while since I've done High School math)

EDIT2: To find values of X, Y, or Z, you must have a second equation that is different from the original with a given value.
« Last Edit: May 06, 2010, 05:06:54 PM by Bleep »

Okay, how about this:

xy + x + y = z
x = (y + z)/x
z = 42

z=42
x=(y+z)/x
xy+x+y=z
(42-x)/(x+1)=y


x^2-y=42 - solve for z = 42; isolate and then substitute into original equation, assuming it's the same X,Y,Z.

xy+x+y=x^2-y  -  You can safely cancel out the single Y's.

xy+x=x^2  -  Plug in Y's equation that we did from my first post.

x(42-x)/(x+1)+x=x^2  -  Multiply the X into the fraction

(42x-x^2)/(x+1)+x=x^2  -  Multiply the denominator to all

(42x-x^2)+(x^2+x)=x^3+x^2  -  Simplify

43x=x^3+x^2  -  Divide by X

43=x^2+x  -  Change this into a quadratic using "Complete The Squares" method

x^2+x+1/4=43-1/4  -  This is result of CTS

(x+1/2)^2=42.75  -  Further simplifying

x+0.5=42.75  -  Solve for X

x=42.25 or 42 1/4 or 169/4

-----------

Plug x into one of the equations from the list, for this I use the simplest one.

x=(y+z)/x - Isolate the Y

x^2-z=y

(42.25)(42.25)-42=y

1743.0625=y  -  Used a calculator for final part.

-----------

EDIT: Now we test our values to see if they're correct.

x=(y+z)/x
z=42
x=42.25
y=1743.0625

42.25=(1743.0625+42)/42.25

1785.0625=1785.0625

If, and only if, you plug this into the FIRST equation (since we used second equation to get values, your answer is correct), the values will be incorrect, so these two equations should never mingle in the first place.
« Last Edit: May 06, 2010, 05:47:38 PM by Bleep »

I just threw together two problems.

Not sure why it won't work for both equations.