If statement not evaluating correctly

[DYLANzzz]

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!(%tr $= %mem.lastTR && %ev $= %mem.lastEV) && %mem.lastTR && %mem.lastEV is evaluated as false

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!(%tr $= %mem.lastTR && %ev $= %mem.lastEV)
%mem.lastTR
%mem.lastEVare all separately evaluated as true

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echo("-----" NL (!(%tr $= %mem.lastTR && %ev $= %mem.lastEV) ? "True" : "False") NL (%mem.lastTR ? "True" : "False") NL (%mem.lastEV ? "True" : "False") NL ((!(%tr $= %mem.lastTR && %ev $= %mem.lastEV) && %mem.lastTR && %mem.lastEV) ? "True" : "False") NL "------");Prints out
------
True
True
True
False
------

Someone tell me what im missing please

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[Treynolds416]

I have a feeling it has something to do with that 'not' at the beginning of the statement

Try (%tr !$= %mem.lastTR || %ev !$= %mem.lastEV) as a replacement for the first one, if I'm reading this correctly it should work the same as !(%tr $= %mem.lastTR && %ev $= %mem.lastEV)

[DYLANzzz]

Nope, still getting the same thing, all evaluate as true except for the full statement

[DYLANzzz]

So apparently

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%mem.lastTR && %mem.lastEVevaluates to false so the problem is coming from this bit.
Can anyone explain to me why? (each also evaluate to true separately)

FIXED IT

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(%mem.lastTR ? 1 : 0) && (%mem.lastEV ? 1 : 0)ended up doing this and now it works

[Port]

FIXED IT

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(%mem.lastTR ? 1 : 0) && (%mem.lastEV ? 1 : 0)ended up doing this and now it works

For something simpler, try (%mem.lastTR) && (%mem.lastEV).