ask me stuff

[Muslim]

clicky click

ask me questions

[Ad Bot]

[Tetris]

are you actually a muslim

[Muslim]

are you actually a muslim

no

[ßlöükfáce]

clicky click

ask me questions

wana forget

[lolz??]

how many more topics will you make today

[Caribou]

Do you actually play golf?

[Insomniac]

What do you think of gore special interestes?

[awesomebread]

If ax*x + bx +c = 0,
then what is x?

[Nal]

is it true you're gay for me

[The Resonte!]

why did you make this thread

how much does a krabby patty cost

on wednesday

[Racerboy]

If ax*x + bx +c = 0,
then what is x?

ax^2+bx+c=0

Complete the square, start by subtracting c from both sides
ax^2 +bx = -c

Divide by a
x^2 +(b/a)x = -(c/a)

add [(1/2)b/a)]^2 to both sides to produce a perfect square trinomial on the right
x^2 +(b/a)x + (b^2)/(4a^2)= (b^2)/(4a^2) - (c/a)

Factor the left side
(x+(b/(2a)))^2 = (b^2)/(4a^2) -(c/a)

Get a common denominator on the right. (multiply -c/a by 4a/4a)
(x+(b/(2a)))^2 = [b^2-4ac]/(4a^2)

Take square root of both side (remember that square root yields a ± solution)
√((x+(b/(2a)))^2) = ±√([b^2-4ac])/(4a^2))

Simplify (√4a^2 = 2a)
x+(b/2a) = ±√([b^2-4ac])/(2a)

Solve for x
x = -(b/2a) ±√([b^2-4ac])/(2a)
x = [-b±√([b^2-4ac)]/(2a)

[Muslim]

is it true you're gay for me

I think you know the answer to that question. Yes.

[awesomebread]

foiled again