math AAAAAAA

[Doomonkey]

I'm probably misunderstanding you completely, but from what I understand you are looking for a coordinate?
if so, could it be (-4, 9)?
if this is right, then I don't understand why you would need to ask for help :I
so I assume that I am wrong

Keep in mind that the graph has a domain of 2. It would be around (-.4,.9)

But in order to be exact you would have to do all sorts of arc crap that I don't feel like looking up how to do.

[Ad Bot]

[cucumberdude]

I'm probably misunderstanding you completely, but from what I understand you are looking for a coordinate?
if so, could it be (-4, 9)?
if this is right, then I don't understand why you would need to ask for help :I
so I assume that I am wrong

You are wrong. Anyways, I gave up on it - effing webassign.

Doomonkey is heading in the right direction.

[cucumberdude]

nvm i got it

you need to take the arc legnth, convert to degrees, use sin and cos trig functions on the angle you got to get the two coords, then adjust their sign based on the quadrant

[Doomonkey]

nvm i got it

you need to take the arc legnth, convert to degrees, use sin and cos trig functions on the angle you got to get the two coords, then adjust their sign based on the quadrant

Was going to start doing it on paper, but you figured it out.

[phflack]

nvm i got it

you need to take the arc legnth, convert to degrees, use sin and cos trig functions on the angle you got to get the two coords, then adjust their sign based on the quadrant

damit, right as i was figuring out how to do it