Author Topic: Math is difficult and my brain is soggy.  (Read 679 times)

Technically it's not soggy, just suspended in cerebrospinal fluid, but anyway.


So I'm working on a continuous physics engine and decided to adapt the continuous interest equation to friction - namely, A = Pert.
This becomes, for a given starting speed S0, coefficient of friction c, and time spent t: St = S0ect.

Now I'm wondering how to get this equation in terms of distance travelled Dt, in the way that if I know Vt = t, then Dt = t2. Does anyone know how to do this?


EDIT: Technically it's St = S0e-ct because the Coefficient of friction is always positive.
« Last Edit: January 28, 2014, 11:56:10 AM by Xalos »


Never have I gotten a headache so quickly. I was going to attempt to assist but I simply haven't the brain power or will to assist. I support you though. :D

Why on earth are you trying to apply the continuous interest equation to friction?

Why on earth are you trying to apply the continuous interest equation to friction?

Because brain! ...no, actually I wanted to cause the speed of a moving object to drop faster when it's moving quickly than when it's moving slowly. Of the formulas I can remember on my own, this seemed like the best fit.

i'm sorry to kind of sidetrack here but how does friction relate to logarithmic growth
does friction increase over time, affecting distance travelled?

i'm sorry to kind of sidetrack here but how does friction relate to logarithmic growth
does friction increase over time, affecting distance travelled?

Friction is correlated to speed - the faster you go, the more friction encountered. (Up to a maximum but I'm ignoring that fact.)
So the friction is a DECAY of speed, so the speed decreases over time.

Wow that was interesting, using PERT for friction. That's fun stuff.


Welp, no one is actually, you know, answering the question I asked, so I'm going to continue trying to figure it out alone. Good work team!