Math Problem (see if you can do it!)

[Blockzillahead]

ABXA=CCC

what the hell does that mean

[Ad Bot]

[SeventhSandwich]

Ok here is a question:

  ABXA=CCC

Find out the sum and what each digit is in the problem. Any letter that shows in the Problem more than once must be the same Digit

I'm gonna try to cut out as much of my work on this as possible so that when Truce shows up he can't badmouth my process :(


So basically, CCC has to be 111, 222, 333, or so on up until 999. It could be '0' if A is allowed to be 0, but that would be too easy so let's ignore that.

Starting with 111, the only factors are 1, 3, 37, and 111, so you could plug in 3 for A, 7 for B, and 1 for C and get:

37 * 3 = 111.

Huh, I guess we didn't even need to try any other other answers...

[SeventhSandwich]

Here's a better question that's a little bit harder:

The product (8)(888...8), where the second factor has k digits, is an integer whose digits have a sum of 1000. What is k?

Straight from everyone's favorite test, the AMC 12.

[Nonnel]

so
 a × b × x × a= c × c × c
correct

I think it's (a × b) × a = c  × c × c????

[Max4344]

inb4 we are doing his homework

[Ipquarx]

Here's a better question that's a little bit harder:

Straight from everyone's favorite test, the AMC 12.

8 * ( 8 * (10^(k+1)-1)/9 ) = 7 (1, k-2 times) 04

7 + k - 2 + 4 = 1000

k = 991

too easy, give more

[Placid]

Here's a better question that's a little bit harder:

Straight from everyone's favorite test, the AMC 12.

oh wtf i didn't think i'd see that question again. although my solution was pretty dumb i guess ill post it.

k=1: 8*8 = 64, sum = 10
k=2: 8*88 = 704, sum = 11
k=3: 8*888 = 7104, sum = 12

if you keep doing this you find that it increases as k does, so sum = 9 + k
k = 991

too easy, give more

here ya go, some of the harder ones from last year's B sitting

[SeventhSandwich]

I never win this damn competition because although I can always solve these, my answers aren't elegant and slightly too slow, so I end up getting to like Q # 18 or 19 and not breaking the 120 mark ;-;

[Placid]

I never win this damn competition because although I can always solve these, my answers aren't elegant and slightly too slow, so I end up getting to like Q # 18 or 19 and not breaking the 120 mark ;-;

i always get to like 15 get paranoid i messed something up in the beginning figure "hey if i get all 15 right i should be good right... right..?" and then go back and check loving everything and rrrrrrrrrrrrrrrr it's such a bad strategy but i do it like every time