Okay, Here is the problem.
f(x) = x
3 -2x
2 -11x +12
The factors of 12 are 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, and -12.
Is there any easier way to find the A, B, and C for the Quadratic formula that isn't synthetic division or long division? For synthetic division, you would need to plug in each factor, and then do a whole line of adding, multiplying, and subtracting (based on if the digits are negative or positive).
A = 1
B = 2
C = -3
Plugging that into the Quadratic formula would get you -2±√2
2-4(1)(-3). This is all divided by 2 (after you solve the top, you solve both equations to find both x intercepts).
so, -2 +4 / 2 = 1, and -2 -4 /2 = -3
The last number of the original string of numbers is the other x intercept (since the x in front is x
3)
So, the final x intercepts are 1, -3, and 12.
help please.
