Ok say you have √164
Like I said, first step is to find 2 multiples in the root to make 164, one being the lowest possible
√164 can become √(2x82), the only problem is that neither 2 or 82 have an exact root, so we have to find another 2 multiples
√164 can then also become √(4x41), and here we have a multiple that has an exact root, 4...
So we do
√4 x √41
2 x √41
2√41.