help with proof forums (Integrated Math 3 :( )

[Waru]

Given: ∠A ≅ ∠E, AB ≅ BE

prove: AD ≅ EC

I got

1. ∠B ≅ ∠B | reflexive property

2. ΔABC ≅ EBD | ASA

so now i have ABC and EBD congruent to each other.. but how the forget do i prove AD ≅ EC now?? is it possible to prove AD ≅ CE and then go from there??

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[Akio]

ad = ec by cpctc probably

edit: cpctc stands for corresponding parts of congruent triangles are congruent so im 90% sure thats it

[Silreath]

1.AD=EC | Seg. Sub. Postulate
You don't need the reflexive prop stuff, just go straight to this.

ad = ec by cpctc probably

edit: cpctc stands for congruent parts of congruent triangles are congruent so im 90% sure thats it

if that was an actual property (i've never seen this before) it wouldve made my 9th grade geometry A TON easier.

[Akio]

this is what it is:
http://www.mathopenref.com/cpctc.html

i don't know if that's the answer they're going for but i remember using it.