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Why the hell won't this work.

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Bloxxed:

I've been trying to use if statements, why isn't this working?

--- Code: ---function call(%var)
{
%var == 5;
if(%var == 5)
{
echo("Over 60!");
}
}

--- End code ---


Headcrab Zombie:


--- Quote from: Bloxxed on October 16, 2010, 10:37:47 AM ---function call(%var)
{
%var = 5;
if(%var == 5)
{
echo("Over 60!");
}
}

--- End quote ---
Also, it isn't a problem, but having %var as an argument is pointless if your just defining it in the function anyways.

Bloxxed:

So how can I solve it, %number1?
hang on I deleted the argument and it still is syntaxing.

Uristqwerty:

What is your code right now?

Bloxxed:

Nono.
It says it's wrong here:
%number1 == 5; ##
##

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