Blockland Forums > General Discussion
How do i post add ons?
FourFlamesNinja:
This is so fun arguing with all these people.
Scout31:
--- Quote from: Scout31 on November 28, 2010, 09:39:32 PM ---I doubt you have the knowledge to hack anything, based off of your spelling and grammar. Plus, I know for a fact that Yahoo changes log-in passwords every 5 minutes, transferred to workers via encrypted satellite signals, then received and decrypted by a small key-chain device. I wouldn't even guess about the government. If you have such 'superior' hacking, programming, and coding knowledge, then you should be able to give me my RL name.
So whats my name? I've found it in several public online places recently. Should be easy for a hacker!
--- End quote ---
DrenDran:
--- Quote from: FourFlamesNinja on November 28, 2010, 10:02:07 PM ---This is so fun arguing with all these people.
--- End quote ---
Yeah, because you're basically trolling then.
Seriously, write up some multi-thousand line C++ applications that use mixtures of Networking and Graphics libraries that actually do something important or relevant and I'll be a bit impressed.
FourFlamesNinja:
What this does is it askes for a number, let's say 3233 (of course i know the RSA encryption has bigger numbers) the only two numbers when multiplied by each other besides 3233 and 1 is (61,53) so any other number besides those four have a GCD with 3233 is 1. So it checks every number up to 3233's square root the numbers and the GCD of them and 3233. It does this until it finds a GCD of not 1. When that is found the number that has the GCD of not 1 is half of the part of the private key. Let's say the number was A. It divides A from N which gives the other part, B. (A-1)(B-1) is then the main part of the private key, you can then use that to find the other part which is not included but can easily be found. If you knew how RSA works you would find that this would work. Remember, I said it would take 5 to 6 years with a Super computer.
FourFlamesNinja:
If you don't understand, sucks.