Randomization

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Randomization

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Jasa 12265:
How would I get a script to call a random function. I was thinking getrandom(function1 , function2 , function3) or something like that.

phflack:
switch(getrandom(1,3))
{
case1:
lalalala;
break;
case2:
lalalala;
break;
case3:
lalalala;
break;
}

that would call a random lalalala, #1-3

MegaScientifical:

--- Code: ---switch(getrandom(1, 3)) {
case 1:
function1(%blah);
case 2:
function2(%blah);
case 3:
function3(%blah);
}
--- End code ---

Why did you put breaks in there, phflack? You also forgot spaces in the case areas and such. Not that you aren't smart, but keep that in mind. :)

Jasa 12265:
I was hoping on making some more common than the other.

--- Code: ---function Function()
{
if(getRandom(1,10) >= 7)
{
Common()
}
if(getRandom(1,10) <= 8)
{
LessCommon()
}
if(getRandom(1,10) == 10)
{
BarelyCommon()
}
}

--- End code ---
But that would call multiple. How would I make it so after one returned true it stopped there?

Chrono:

--- Quote from: Jasa 12265 on December 15, 2010, 07:53:50 PM ---I was hoping on making some more common than the other.

--- Code: ---function Function()
{
if(getRandom(1,10) >= 7)
{
Common()
}
if(getRandom(1,10) <= 8)
{
LessCommon()
}
if(getRandom(1,10) == 10)
{
BarelyCommon()
}
}

--- End code ---
But that would call multiple. How would I make it so after one returned true it stopped there?

--- End quote ---
Do this

--- Code: ---function Function()
{
%r = getRandom(1,10);
if(%r == 10)
{
BarelyCommon()
}
else if(%r <= 7)
{
Common()
}
else if(%r >= 8)
{
LessCommon()
}
}
--- End code ---

The problems in yours include:
10's if would never get called from the bottom.
Wrong < and >
Lacking else, which only calls one of the ifs.
And it's getting a new random number for each if statement.

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