Blockland Forums > Modification Help
[SOLVED] Using strLen, and strStr in a function
Greek2me:
--- Quote from: FFSO on December 10, 2011, 11:18:25 PM ---I was trying to make it check if the word had any letter in the alphabet. Ill correct in the morning.
--- End quote ---
Then you would do something like this:
--- Code: ---function stringHasLetter(%string)
{
%alphabet = "a b c d e f g h i j k l m n o p q r s t u v w x y z";
for(%i=0; %i < getWordCount(%alphabet); %i++)
{
if(strPos(%string,getWord(%alphabet,%i)) >= 0)
return 1;
}
return 0;
}
--- End code ---
If the string has any letter in it then this will return true.
Destiny/Zack0Wack0:
That's a pretty slow method to do it, something like this is better:
--- Code: ---function stringHasLetter(%string)
{
if(%string $= "")
return false;
return stripChars(%string,"abcdefghijlmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ") !$= %string;
}
--- End code ---
Also proof that it's slower:
Average time for 5x 100,000 iterations of my method: 3327 milliseconds.
Average time for 5x 100,000 iterations of your method: 4277 milliseconds.
FFSO:
There was supposed to be 2 strings since it is using strStr(%string, %string2);
so...would it be
--- Code: ---function stringHasLetter(%string, %string2)
{
if(%string $= "" || %string2 $= "")
return false;
return stripChars(%string,"abcdefghijklmonpqrstuvwxyzABCDEFGHIJKLMONPQRSTUVWXYZ") !$= %string & %string2;
echo(strStr(%string, %string2));
}
--- End code ---
??? I was just winging it but it looks correct.
EDIT: Doesn't echo but the function has no syntax errors, apparently echo(strStr(%string, %string2)); is not working,
Headcrab Zombie:
Because you're returning before the echo.
Also this:
--- Code: ---%string & %string2
--- End code ---
I'm not sure what you're trying to do here, but I don't think you're doing what you think you're doing. Using bitwise operators on strings will always return 0 if the string isn't/doesn't start with a number.
Are you maybe trying to do something like this?
--- Code: ---%stripped = stripChars(%string,"abcdefghijklmonpqrstuvwxyzABCDEFGHIJKLMONPQRSTUVWXYZ");
%result = %stripped !$= %string && %stripped !$= %string2;
--- End code ---
Greek2me:
I think I know what he wants now. He just wants to check if the string has a specific letter in it.
--- Code: ---function stringHasLetter(%string,%letter)
{
if(%string $= "" || %letter $= "")
return false;
return (strPos(%string,%letter) >= 0);
}
--- End code ---
So then stringHasLetter("blah blah blah","e"); would return false and stringHasLetter("blah blah blah","a"); would return true.