Blockland Forums > Modification Help
Creating a datablock using a variable name
DYLANzzz:
Just reread what brian said. I didnt see that last line there. Thanks, that worked!
Xalos:
The reason your first eval attempt didn't work is because you can't break strings across multiple lines.
--- Code: (No!) ---echo("This is
a test.");
--- End code ---
--- Code: (Yes!) ---echo("This is"
@"a test.");
--- End code ---
--- Code: (Yes!) ---echo("This is"@
"a test.");
--- End code ---
--- Code: (No!) ---echo("This is"@
@a test.");
--- End code ---