Why won't this work?

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I-have-not:
I'm trying to make it echo
1
2
3
4
5
6
7
8
9
10
by using this script in console :
function count(%y){ %y=0; if(%y != 10){echo(%y++);}}
but for some reason it only echoes:
1
why won't this script work? Any help please?

Brian Smithers:
function test(%y)
{
for(%i=0;%i<%y;%i++)
echo(%y);
}
Fixed :)

for(statement used on start; statement check for end; statement used when finished)
{
your work
}
:)

I-have-not:

--- Quote from: Brian Smithers on January 22, 2012, 11:55:43 PM ---function test(%y)
{
for(%i=0;%i<%y;%y++)
echo(%y);
}
Written on my iPad c:

--- End quote ---
This makes no sense to me? line 2 makes no sense. I don't understand, it could be easier if you explained.

soba:

--- Quote from: Brian Smithers on January 22, 2012, 11:55:43 PM ---function test(%y)
{
for(%i=0;%i<%y;%y++)
echo(%y);
}
Written on my iPad c:

--- End quote ---
Wouldn't this only echo once?

resulting in you needing to enter it 10 times to get the desired result?

and @OP, you don't actually alter the value, you echo it with a +1, and since the value is 0, it will always echo 1

Gadgethm:

--- Quote from: soba on January 23, 2012, 12:18:29 AM ---Wouldn't this only echo once?

resulting in you needing to enter it 10 times to get the desired result?

--- End quote ---
No, the echo is run on every loop. The for loop runs for an infinite number of times until %i>=%y then it stops. So test(%y) would count up to whatever number you put in and echo each time it counts.

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