Author Topic: Plate has 205 million studs  (Read 4601 times)

I thought 1 TU was 2 studs, which would make 6 plates, but either way it blows
ports estimation way out of proportion.
A brick is 0.5 TU by 0.5 TU by 0.6 TU
So, a TU is either 2 studs across or 5 plates up

either way it blows ports estimation way out of proportion.


Where the hell are you getting that from?

There is a total flat surface area of 205520896 bricks, multiplied by height

The height is 19999980 TU multiplied by 6 (1 TU = 2 studs = 6 plates), which is 119999880.

So that's 205520896 multiplied by 119999880, which comes out to be 24,662,482,857,492,480.

Here's a precise calculation.

Height from plate up to where it starts getting glitchy: 999999 TU
Height from plate down to where it starts getting glitchy: 999999 TU
Total height: 999999 * 2 = 1999998
Total width: --- || ---
Total length: --- || ---
Total area (3D): 19999983 = 7999976000023999992
In studs (3D): 7999976000023999992 * 2 = 15999952000047999984

((999999 * 2) ^ 3) * 2 = 15999952000047999984
« Last Edit: June 06, 2012, 02:12:01 AM by Port »

That's different than your other number port...
But I can see a few differences between the maths.
- ip is using 19999980 for height, you are using 1999998
- you aren't using the area value, this may or may not affect the outcome
- you are calculating the area in non-existent 0.5x TU brick cubes, ip is (trying to) do it in plates
- that number is different from your last one!

I pass no judgement on these differences, just saying they are there is all

- you aren't using the area value, this may or may not affect the outcome

The volume of a 3D cube is it's width multiplied by it's length multiplied by it's height.

- you are calculating the area in non-existent 0.5x TU brick cubes, ip is (trying to) do it in plates

I'm calculating it in studs (1x cubes, essentially).

The volume of a 3D cube is it's width multiplied by it's length multiplied by it's height.

I'm calculating it in studs (1x cubes, essentially).
Which don't exist. You are using a cube made out of square studs. A real 1x1 brick has the dimensions 0.5 x 0.5 x 0.6.
I'm pretty sure you already knew this, why not use a more relatable unit instead of a fake one?

and now for something completely different:
the blockland forums argue about math

and now for something completely different:
the blockland forums argue about math
Nah they do that on off-topic sometimes

lol i found something if any one thinks it would be useful
16x16=5in.
32x32=10in.
This makes that the Aegis would be 3.08 meters which is twice the length of forum user Vegetarian Zombie.

that is one long snake, veg

Here's a precise calculation.

Height from plate up to where it starts getting glitchy: 999999 TU
Height from plate down to where it starts getting glitchy: 999999 TU
Total height: 999999 * 2 = 1999998
Total width: --- || ---
Total length: --- || ---
Total area (3D): 19999983 = 7999976000023999992
In studs (3D): 7999976000023999992 * 2 = 15999952000047999984

((999999 * 2) ^ 3) * 2 = 15999952000047999984
Way off buddy.
Though mine was off too, apparantly, so here's a correct version.

The givens:
width = 14,336
length = 14,336
height = 4,999,995 (999999 TU * 5 plates for 1 TU)

The formula:
volume = width * length * height

so the volume is 14,336*14,336*4,999,995.

And that comes out to be a grand total of:
1,027,603,452,395,520 1x1f plates that can be fit into the non-glitchy area of slate.

you can have surface area of 3D objects but nice try

Wrong.

Surface area of a 3D object is a 2D representation of itself as if it was laid flat.

Way off buddy.

How was I off?

width = 14,336
height = 14,336

wtf are you talking about