Math Problems

[ThinkInvisible]

A car, at 4.4 seconds, travelled 56 kilometers. The car has travelled 128km by 15 seconds. Find the rate of speed at which the car went between the two points and show your work.

56km = 4.4s
128km = 15s

V = D / T equation:
D = 128km - 56km = 72km
T = 15s - 4.4s = 10.6s

Unit conversion:
               |60s |
T = 10.6s|-----|10.6 / 60 = 0.1766666...
               |1h  |

V = D / T part two:
V = 72km / 0.177s = 406.779661017...

Speed is 406.7797km/h.

[Ad Bot]

[Treynolds416]

A car travels 48 mph for a distance and then 72 mph for that same distance. What is it's average speed.

Let's assume exactly 144 miles is the distance. The first leg takes three hours, the second leg takes two. (72 + 72 + 48 + 48 + 48) / 5 = 57.6 mph average. Since the legs are proportional, whatever distance it is really doesn't matter, so you can make it anything you want

[ThinkInvisible]

A force of 35n at 74°θ, 140°φ and a force of 60n at 267°θ, 20°φ are both acting upon an object. What is the net force acting on the object?

[Ipquarx]

ANSWER:

sqrt(3)^¾
(3^½)^¾
3^3/8
8/3^sqrt(3)

kind of difficult but yeah

*facedesk*

here's an inequality question that I made especially for you guys:
9x-7i > 3(3x-7u)

[Doomonkey]

Let's assume exactly 144 miles is the distance. The first leg takes three hours, the second leg takes two. (72 + 72 + 48 + 48 + 48) / 5 = 57.6 mph average. Since the legs are proportional, whatever distance it is really doesn't matter, so you can make it anything you want

Exactly. The average speed is 57.6 mph. There are a wide variety of ways to find this. You can use Treynolds' method. You can use a proportion of the reciprocals of the speeds, because you travel the same distance at a higher speed in less time, and the time for the speeds is proportionate to the reciprocals of the speed. Or you can use the formula D=Rt to and some algebra rewrite the average rate in terms of D/D, which cancels out and gets you a rate.

[Treynolds416]

A force of 35n at 74°θ, 140°φ and a force of 60n at 267°θ, 20°φ are both acting upon an object. What is the net force acting on the object?

That's a lame question. Problems like that are just a useless exercise in typing trigonometric functions, there's no thinking involved, you just need to know how to trig. Why not come up with an actual word problem

[lolz??]

I made you all an equation:

E=MC^2

now figure out without any outside help and show your working.

[Doomonkey]

I made you all an equation:

E=MC^2

now figure out without any outside help and show your working.

Alright. Because there are two variables I'll define one to solve the problem. M=0. Therefore E=0. Solved.

[ChexGuy331]

I made you all an equation:

E=MC^2

now figure out without any outside help and show your working.

Dumb bitch, there's nothing to solve.

[lolz??]

Alright. Because there are two variables I'll define one to solve the problem. M=0. Therefore E=0. Solved.

now make table to show all possible solutions

Dumb bitch, there's nothing to solve.

well done, you are a true prodigy

[ultimamax]

now make table to show all possible solutionswell done, you are a true prodigy

That is literally infinite. Any variable could be any number.
Someone post a real math problem plz

[lolz??]

That is literally infinite.

<shhh.

This now seems to be about solving random equations instead of helping with elecro's homework and whatnot apperantly.

[Blockomanian]

y-3x=5
y+x=3

Solve with substitution.
Should be extremely easy if you know what do.

[tikitai]

y-3x=5
y+x=3

Solve with substitution.
Should be extremely easy if you know what do.

x=-0.5
y=3.5

[kevin 51l]

x = -0.5
y = 3.5




solve for x if angle 1 is 146.73


(i actually made this in javascript where angle 1 is a random number for computer science might give link to if i feel like it)


Edit:

x=-0.5
y=3.5

I SAW YOU

YOU SAID y=2.5

WHAT A DUMBASS