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Calling all physics nerds! I am dumb as a box of rocks
bithead9:
--- Quote from: Col. Derontchi on January 25, 2017, 10:14:20 PM ---it is proper. And I don't really have anywhere else. I've spent hours on this.I've estimated the angle from the wall to be about 79 degrees. The ground is irrelevant. My teacher put that there when he was helping me out but it might have been torque. I don't remember which.
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I was just using the ground as a way to communicate a horizontal flat line.
These are the numbers I got, I'm not that confident in all of them, but I'll also give some work. (I didn't get to everything as I really need some sleep)
the force of gravity is 27.048N because I converted 6.1 pounds to kg and multiplied by 9.8
The net torque is of course 0 Nm, but I found that gravity and the normal force apply a torque of 104 Nm
(because the pivot location we can neglect the top forces) Therefore, Fg*r = Fn1*r
We know Fg (27.048) and r is 29 inches (converted to meters, .7366m)/cos(79))
This means that the moment arm is 3.86m (this is where I'm unsure, I was never really good at torque)
Multiply those two numbers together to get ~104 Nm
I didn't get to the other normal force or the tension, but you know Fg and Fn1 are the same value, and the sum of all the forces in the y direction are
Fg = Fn2 + Tcos(79)
and in the x direction are
Fn1 = Tsin(79)
Good luck, hopefully I'm not an idiot and made a ton of mistakes.
Col. Derontchi:
--- Quote from: bithead9 on January 25, 2017, 10:41:34 PM ---I was just using the ground as a way to communicate a horizontal flat line.
These are the numbers I got, I'm not that confident in all of them, but I'll also give some work. (I didn't get to everything as I really need some sleep)
the force of gravity is 27.048N because I converted 6.1 pounds to kg and multiplied by 9.8
The net torque is of course 0 Nm, but I found that gravity and the normal force apply a torque of 104 Nm
(because the pivot location we can neglect the top forces) Therefore, Fg*r = Fn1*r
We know Fg (27.048) and r is 29 inches (converted to meters, .7366m)/cos(79))
This means that the moment arm is 3.86m (this is where I'm unsure, I was never really good at torque)
Multiply those two numbers together to get ~104 Nm
I didn't get to the other normal force or the tension, but you know Fg and Fn1 are the same value, and the sum of all the forces in the y direction are
Fg = Fn2 + Tcos(79)
and in the x direction are
Fn1 = Tsin(79)
Good luck, hopefully I'm not an idiot and made a ton of mistakes.
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Everything looks good to me. I don't really remember torque so I don't know though. I really appreciate it either way.
If anyone else would like to evaluate it, that's fine too.