finding legs given hypotenuse and angles of triangle

[thegoodperry]

title is basically given. i have a random right triangle which i know the hypotenuse and all the inside angles of. i need to find the legs

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[Darryl McKoy]

found them

[thegoodperry]

thank you so much, locking thread

[Daswiruch]

sohcahtoa? i vaguely remember doing this in pre-calc but i dont think this is correct

[Woof]

forget about the triangle's legs
my legs are in the air bb <3

[Daswiruch]

sohcahtoa? i vaguely remember doing this in pre-calc but i dont think this is correct

https://www.youtube.com/watch?v=Uxo_JCp44A8 - SOH CAH TOA - finding side lengths

[Tetris]

use Pythagorean theorem to solve for a/b

[Khaz]

use sohcahtoa and trig. ratios and then pythagorean theorem

if you wanna be lazy theres a few online calculators

[thegoodperry]

use Pythagorean theorem to solve for a/b

use sohcahtoa and trig. ratios and then pythagorean theorem

if you wanna be lazy theres a few online calculators

i need steps

i cant use a calculator im coding something

[Conan]

basic trig

given triangle with sides A B C and angles a b c (angle name being the angle directly opposite of the side), and C being the hypotenuse (making c 90 deg)

sin(a) * C = A
cos(a) * C = B
tan(a) * B = A

basically if you have two sides and an angle of a right triangle, or one side and two angles, you can solve for the whole thing

make sure your angle is in radians cause thats how 99% of all languages handle trig

[Mardalf]

I wish I was high on potenuse

[Conan]

I wish I was high on potenuse

bro...... jordan said that.....

[Lumen]

nerds

[Kearn]

assuming you have your angles given in degrees and using dummy values

angle_a = 50;
angle_b = 40;
hypotenuse = 32;

angle_a_rad = angle_a*pi/180;
angle_b_rad = angle_b*pi/180;

A = hypotenuse*sin(angle_a_rad) %opposite angle a
B = hypotenuse*sin(angle_b_rad) %opposite angle b

theres your matlab code nerd

[The Subject]

yo, if all you know are the angles then the triangle can be any size