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| Impossible Math |
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| fireball:
--- Quote from: Draco S. on July 29, 2009, 12:05:22 AM ---I do believe that's x MINUS y. --- End quote --- I'll try explaining it another way. x = y is what the equation started out as. x - y = 0 since x is always equal to y, subtracting the y is essentially the same as subtracting a number from itself which always gives you 0. I can replace x - y with 0 because they equal each other. So by dividing out the x - y, he was really dividing by 0 which broke the problem. |
| Inv3rted:
There was no division in the whole problem. You're an idiot. |
| Gamefandan:
--- Quote from: toast$$$hero on July 29, 2009, 12:01:07 AM ----snip- --- End quote --- Nice page stretch. OLOLOLOLOL I'M WAY OVER HERE! :D |
| fireball:
You sir, are the idiot! (x+y)(x-y) = y(x-y) Here is the step where the division occurs. Watch closely! (x+y)*(x-y) = y*(x-y) Two parenthesis next to each other or a number/variable next to the parenthesis means multiplication. (x+y)*(x-y)/(x-y) = y*(x-y)/(x-y) The same thing is being multiplied on both sides. To undo this, we have to DIVIDE by the same number on both sides. (x+y)*(x-y)/(x-y)1 = y*(x-y)/(x-y)1 Oshi! The two operations canceled each other out! (x+y)*1 = y*1 Anything divided by itself equals one. Just what we wanted because 1 is the identity for multiplication! Anything times 1 equals itself. (x+y) = y Almost there. We can get rid of the parenthesis now because the only operation being done is addition. x+y = y OMFG! We just got to the next step of the problem using division! Too bad it completely destroys the problem because the division just happened to be 0. Tard |
| Travis [bob36455]:
mathmakemybrainhurt. It equals |
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