| Off Topic > Off Topic |
| Impossible Math |
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| FlyGuy45:
I've seen this problem before, or something like it, its just a hidden / by zero proof of some sort. |
| AGlass0fMilk:
They are imaginary numbers because if x=y, then x+y cannot possibly = y They are imaginary numbers, thus they don't really exist. </thread> |
| Inv3rted:
--- Quote from: AGlass0fMilk on July 29, 2009, 12:50:42 PM ---They are imaginary numbers because if x=y, then x+y cannot possibly = y They are imaginary numbers, thus they don't really exist. </thread> --- End quote --- LOL. Try making them both 0, you loving idiot. |
| AGlass0fMilk:
Oh. If they are both 0, then it's all just 0. I don't see why it's so hard then. Dividing by 0 would just equal that number since there is nothing to divide by, or would it equal 0? Since they are all 0 it would equal zero anyways, or would it? |
| FlyGuy45:
--- Quote from: AGlass0fMilk on July 29, 2009, 12:51:48 PM ---Oh. If they are both 0, then it's all just 0. I don't see why it's so hard then. Dividing by 0 would just equal that number since there is nothing to divide by, or would it equal 0? Since they are all 0 it would equal zero anyways, or would it? --- End quote --- LOL. |
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