Off Topic > Off Topic
Impossible Math
FlyGuy45:
I've seen this problem before, or something like it, its just a hidden / by zero proof of some sort.
AGlass0fMilk:
They are imaginary numbers because
if x=y, then x+y cannot possibly = y
They are imaginary numbers, thus they don't really exist.
</thread>
Inv3rted:
--- Quote from: AGlass0fMilk on July 29, 2009, 12:50:42 PM ---They are imaginary numbers because
if x=y, then x+y cannot possibly = y
They are imaginary numbers, thus they don't really exist.
</thread>
--- End quote ---
LOL.
Try making them both 0, you loving idiot.
AGlass0fMilk:
Oh.
If they are both 0, then it's all just 0. I don't see why it's so hard then.
Dividing by 0 would just equal that number since there is nothing to divide by, or would it equal 0? Since they are all 0 it would equal zero anyways, or would it?
FlyGuy45:
--- Quote from: AGlass0fMilk on July 29, 2009, 12:51:48 PM ---Oh.
If they are both 0, then it's all just 0. I don't see why it's so hard then.
Dividing by 0 would just equal that number since there is nothing to divide by, or would it equal 0? Since they are all 0 it would equal zero anyways, or would it?
--- End quote ---
LOL.