A sudden emurgence of christian nuts...

[Doomonkey]

You really have no loving idea what you're talking about. You can prove plenty of things. I suppose mathematics flew over your head in school, eh?

Prove there isn't a universe in your ear.

[Ad Bot]

[MtnDew]

You really have no loving idea what you're talking about. You can prove plenty of things. I suppose mathematics flew over your head in school, eh?

Seriously, You should have just read what he said.
Instead of trying to prove him wrong on whether or not to call it a theory.

[Tingalz]

This thread has crashed and is going nowhere.

[Inv3rted]

Prove there isn't a universe in your ear.

That doesn't mean nothing can be proved. Your statement was flawed.

[kyle222]

Dillpickle? That forgettard.
He banned me for calling him dillie.

[Kalphiter]

"Removed DM Church save due to jesus nuts complaining"

[.::Taboo::.]

"Removed DM Church save due to jesus nuts complaining"

[-Mike-]

"Removed DM Church save due to jesus nuts complaining"

aw i liked it D:

anyone have a save?

[Doomonkey]

That doesn't mean nothing can be proved. Your statement was flawed.

Prove anything.

[Inv3rted]

Prove anything.

Alright.

[MtnDew]

Seriously, You should have just read what he said.
Instead of trying to prove him wrong on whether or not to call it a theory.

[Inv3rted]

Balls, wrong image. One second.


Proof. Let q be a point on the other side of L from p. Let \alpha be the circle through q with center p. Let a and b be the intersection points of L and \alpha. By Proposition I.10, let d bisect the segment from a to b. Let M be the line through p and d. By Proposition I.8, \angle pda = \angle pdb, hence L and M are perpendicular.

[Inv3rted]

Taken from: http://www.unwantedcapture.org/2009/05/27/euclidean-proof-part-1/

[Doomonkey]

Balls, wrong image. One second.


Proof. Let q be a point on the other side of L from p. Let \alpha be the circle through q with center p. Let a and b be the intersection points of L and \alpha. By Proposition I.10, let d bisect the segment from a to b. Let M be the line through p and d. By Proposition I.8, \angle pda = \angle pdb, hence L and M are perpendicular.

What if that circle has 361 degrees. Then L and M are not. Prove it doesn't have 361 degrees.

[Inv3rted]

What if that circle has 361 degrees. Then L and M are not. Prove it doesn't have 361 degrees.

A circle can't have 361 degrees...