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| Need help on algebra 2 homework |
| << < (6/6) |
| tay104:
forget imaginaries. I hate them with a passion. |
| Deathwishez:
Cubing: x3-1000 What got cubed? (x-10) What's the trinomial? Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x) It will look like this: (x-10)x2+10x+100 Got it? |
| Tom Gunn:
(x-10)(x - 5 + i5sqrt(3) ) ( x-5 - i5 sqrt(3)) |
| DrMobius:
--- Quote from: Deathwishez on November 18, 2009, 05:05:18 PM ---Cubing: x3-1000 What got cubed? (x-10) What's the trinomial? Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x) It will look like this: (x-10)x2+10x+100 Got it? --- End quote --- get the forget out you handicap. |
| Healbadbad:
--- Quote from: Deathwishez on November 18, 2009, 05:05:18 PM ---Cubing: x3-1000 What got cubed? (x-10) What's the trinomial? Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x) It will look like this: (x-10)x2+10x+100 Got it? --- End quote --- NO. your logics: (x-10)^3=x^3-1000 (x-10)(x-10)(x-10)=x^3-1000 (x^2-20x+100)(x-10)=x^3-1000 x^3-10x^2-20x^2-200x+100x-1000=x^3-1000 X^3-30x^2-100x-1000=x^3-1000 -30x^2 -100x = 0 -30x^2 = -100x -30x=100 x=-100/30 Real logic: X^3-1000=0 X^3=1000 cube root both sides X = 10 |
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