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Need help on algebra 2 homework
tay104:
forget imaginaries. I hate them with a passion.
Deathwishez:
Cubing:
x3-1000
What got cubed?
(x-10)
What's the trinomial?
Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x)
It will look like this:
(x-10)x2+10x+100
Got it?
Tom Gunn:
(x-10)(x - 5 + i5sqrt(3) ) ( x-5 - i5 sqrt(3))
DrMobius:
--- Quote from: Deathwishez on November 18, 2009, 05:05:18 PM ---Cubing:
x3-1000
What got cubed?
(x-10)
What's the trinomial?
Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x)
It will look like this:
(x-10)x2+10x+100
Got it?
--- End quote ---
get the forget out you handicap.
Healbadbad:
--- Quote from: Deathwishez on November 18, 2009, 05:05:18 PM ---Cubing:
x3-1000
What got cubed?
(x-10)
What's the trinomial?
Square the first (x)>(x2), square the last (-10)>(100), opposite sign (-)>(+), product of the two (x-10)>(-10x)
It will look like this:
(x-10)x2+10x+100
Got it?
--- End quote ---
NO.
your logics:
(x-10)^3=x^3-1000
(x-10)(x-10)(x-10)=x^3-1000
(x^2-20x+100)(x-10)=x^3-1000
x^3-10x^2-20x^2-200x+100x-1000=x^3-1000
X^3-30x^2-100x-1000=x^3-1000
-30x^2 -100x = 0
-30x^2 = -100x
-30x=100
x=-100/30
Real logic:
X^3-1000=0
X^3=1000
cube root both sides
X = 10