Author Topic: This riddle I found  (Read 5625 times)

I belive to win you have to think outside of the box, but thus far I am starting to wonder if it is possible.

16 - 6 = 10
10 / 4 = 2.5
I don't think you can have 2.5 circles in each row while sustaining 4 rows, unless I am missing a step.


O O O O
X O O X
X X O O
O X O X

It has to be it

O O O O
X O O X
X X O O
O X O X

It has to be it
Nope

I belive to win you have to think outside of the box, but thus far I am starting to wonder if it is possible.

16 - 6 = 10
10 / 4 = 2.5
I don't think you can have 2.5 circles in each row while sustaining 4 rows, unless I am missing a step.
It will only work if you have a cube in the end

You'll only get a cube if you take away 7 circles:
o o o
o o o
o o o

It really isn't possible.



row 1, 2 and 4 have 2 o's left!

I belive to win you have to think outside of the box, but thus far I am starting to wonder if it is possible.

16 - 6 = 10
10 / 4 = 2.5
I don't think you can have 2.5 circles in each row while sustaining 4 rows, unless I am missing a step.
( ( ( O
( ( O )
( O ) )
O ) ) )

???

wtf, explain why
row 1: 4c
row 2-3: 2c

columm 3: 4c
column 1,2,4: 2c

c=circles


Look. First line down:
O
X
X
O

This equals 2 O's

Second line down:
O
O
X
X

This also equals 2 O's.

3rd line down:
O
O
O
O

Fourth row down:
O
X
O
X

Being 2 AGAIN, which is equal.

1st row across:
O O O O

All 4.

2nd row across:
X O O X

2 O's yet again.

3rd row across:

X X O O

2 O's yet again.

4th row across:
O X O X

2 O's!
« Last Edit: April 11, 2010, 01:30:16 PM by Big Brother »

OK, this puzzle is only possible if you consider being able to chop the circles in half :3

its all even, as you just said. 4 2 4 2, where is there a 3 or a 1
What.
You said equal number of circles, not even numbers.