Math

[Deathwishez]

I can't seem to remember how to do this kind of problem:

xy + x + y = z

I need to solve for x and y.

Can anyone here help me out?

[Ad Bot]

[Madmitten]

what is z?

[Deathwishez]

z is a variable.

[oromis]

Sure thing brosef

2x=z-2y

2y=z-2x

you just move all variables BUT the solving one over the equals sign.

[Deathwishez]

Sure thing brosef

2x=z-2y

2y=z-2x

you just move all variables BUT the solving one over the equals sign.

Steps please. I can't see how you got that.

The xy is making my life hard. I can't get rid of it to leave x or y behind without screwing up the other variables.

[oromis]

xy is equal to x times y.

Steps?

xy+x+y=z
--combine x's and y's
2x+2y=z
--solve by moving over equals

2x=z-2y
or
2y=z-2x

[Deathwishez]

That doesn't work...

xy != x + y

xy + x + y != 2x + 2y

I wouldn't have come here if that was the case.

[oromis]

That's what xy means, unless xy is another variable, but there is no point to have xy as another variable, there are plenty other letters in the alphabet.

[|Shadow]

xy is equal to x times y.

Steps?

xy+x+y=z
--combine x's and y's
2x+2y=z
--solve by moving over equals

2x=z-2y
or
2y=z-2x

Can't add xy to x+y, doesn't work like that.
eg (just making up numbers here)
let's say x = 2 and y = 3

(2x3)+(2)+(3)=11

if we sub x = 2 and y = 3 into your equation,

2(2)+2(3)=10


edit
is this a problem you were given or is it made up?

[Raider.]

what is z?

lol'ed

[Bleep]

xy+x+y=z

For X:

x(y+1)+y=z
x(y+1)=z-y
x=(z-y)/(y+1)

now for Y:

y(x+1)+x=z
y(x+1)=z-x
y=(z-x)/(x+1)

[Sandvich]

Sandvich needs numbers to solve things :(

[Bleep]

Sandvich needs numbers to solve things :(

He didn't ask for numbers, he only wanted X and Y. So all you had to do was isolate them using distributive property to make it only one of that kind of variable you're looking for.

[Sandvich]

He didn't ask for numbers, he only wanted X and Y. So all you had to do was isolate them using distributive property to make it only one of that kind of variable you're looking for.

Let me rephrase that

Sandvich needs atleast 1 number before hes confused
If they had a number say, x=10 and y=20
(10x20)+(10)+(20)=230
So z would = 230 in that situation

I think ...

I'm and 6th and making c's and d's in math, screw this

[Bleep]

I never got anything below a B+ in math...and I'm currently in Calculus 3 in university. ;/