Help with my science HW.

[xSiZzle]

See my old post.

Could you help me solve that out. Quit hard to understand.

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[Mega-Bear]

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[Doomonkey]

Could you help me solve that out. Quit hard to understand.

There are two formulas for a ball being thrown straight up:

One for finding times that a ball is at a specific height: H=at²+bt+c
H is the height for which you are finding the times.
a is 1/2 of gravity
t is the time (you are trying to find that)
b is the initial velocity
c is the initial height

The one for finding the time of the vertex (highest point): -b/2a=t
Refer to the first formula for a and b.
Plug in the time from this formula into the first formula in order to get the height of the vertex.

[|Shadow]

Im thinking 100m, because from second 1 to second 2, it goes 40 M. Reason is at the start Gravity makes it decrease by 10 m/s. from 2 to3, its 30. So 40 + 30 = 70. From 3 to 4, its 20, so now were at 90. In the last second it goes 10 m/s so I think it 100m not sure though.

150m, you forgot "from second 0 to 1 it goes 50m"