Author Topic: HW Question  (Read 1141 times)

With or without replacement?

Without replacement, I've taken Probabilities and Statistics and we had to do that stuff ALL the time.

I think nonsensical math is hilarious.

I saw that ninja, now I have to do it over, ihu.

I saw that ninja, now I have to do it over, ihu.

You only have to change one letter lul

Seriously? Why would you make this topic? Or even a profile. Google it for God's sake you douche bag.

You only have to change one letter lul

I don't even know what that means but I'mma take a crack at it anyways. I learned this not even a year ago and I can't remember it now.

-2 black jacks and an ace
52/10625

-10 of diamonds and two black 5s
1/42500
« Last Edit: October 05, 2011, 05:34:38 PM by orange wolf »

I don't even know what that means but I'mma take a crack at it anyways. I learned this not even a year ago and I can't remember it now.

-2 black jacks and an ace
52/10625

sorry but u r rong

(2C2 * 4C1) / 52C3 = 0.01089954751%

-10 of diamonds and two black 5s
1/42500

agen thou art wrongeth

(1C1 * 2C2) / 52C3 = 0.004524886878%

Lern2math imo
« Last Edit: October 05, 2011, 05:42:22 PM by Stocking »

I guess I can't be a millionaire.

This topic is getting weirder and weirder. lol

sorry but u r rong

(2C2 * 4C1) / 52C3 = 0.01089954751%

agen thou art wrongeth

(1C1 * 2C2) / 52C3 = 0.004524886878%

Lern2math imo
wtf

aren't you like 13?

Nobody is going to do your homework for you.

What? A Black Jack or blackjack?

For a black jack it's 2/52

1/52 for a 10 of diamonds.

13/52 for red club

1/52 for a two of spades

26/52 for any black card

A red picture card?

Orange Wolf is clearly a scholar who is in pursuit of knowledge.  I was not expecting that :P

Orange Wolf is clearly a scholar who is in pursuit of knowledge.  I was not expecting that :P

And yet I couldn't answer Stockings' version even though I've already learned it. I think I'll just stick to science, haha.

wtf

aren't you like 13?
Profile says 15.
I learned that stuff last year.

C
What does this operation mean?

Wouldn't you just multiply the individual probabilities?

2/52 for the first black jack, 1/51 for the second, 4/50 for the ace.