Author Topic: Mathematics help, please (Read 1049 times)

Big Brother · November 20, 2011, 10:15:51 AM

Yeh...I'm not exactly very good at maths, especially stuff like this. If anyone knows how to solve this, please do tell me lol

~~We've been given an assortment of questions like these, so if these three get solved I have a few more, lol~~

theres a new question dhdhdf

And to clarify, yes I am asking for maths help @ the blockland forums, thanks! :D

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Gojira · November 20, 2011, 10:17:42 AM

find the angle that makes the triangle's angles add up to 180º

Chefkokkie · November 20, 2011, 10:20:51 AM

A right corner is 90 degrees.
A triangle's corners add up to 180 degrees.
A rectangle's corners add up to 360 degrees.
An equilateral triangle has 3 corners of 60 degrees.
In an isosceles triangle two of the corners are identical.

In the first one, there's triangle ABE. Since in total it is 180 and it has a corner with 42 and 90, the last corner has to be 180-42-90=48
Because in total E has to have 180 degrees (half a circle) and one part of it is 61, and another is 48, that leaves x=180-61-48=71

If you want me to I can solve the other ones but this should help.

Big Brother · November 20, 2011, 10:22:52 AM

So for the first one x is 71? woo, thank you :D

I'd appreciate it lots if you did the other ones too c:

Chefkokkie · November 20, 2011, 10:28:52 AM

I did the SUBTRACTION and ADDITION in my head so I might've messed up but yeah that's what I got.

For the second one:
Since XYZ is equilateral, all it's angles are 60 degrees. All of Z's angles have to add up to 180, so Z's angle in triangle XZW is 180-60=120. Since the angles in ZXW have to add up to 180, x=180-35-120=25

The last one:
In PQR, Q=R (because it is isosceles). And because all R's angles have to add up to 180 since it's on a straight line, R in triangle SPR is 180-69=111. Because all the angles in triangle SPR have to add up to 180, x=180-111-35=34.

indyjones · November 20, 2011, 10:29:47 AM

B is 25*
C is 34*

EDIT:

inafterchef :c

Big Brother · November 20, 2011, 10:32:15 AM

Awesome, you got them all correct. Thank you very much! Mind helping me with the second piece?

These are angles which are parallel, this is part 1/2

This one's a little easier thankfully

first one is 54 i think

Chefkokkie · November 20, 2011, 10:34:18 AM

1st x=54
2nd x=113
3rd x=121
4th x=109
5th x=67
6th x=112

nienhaus1 · November 20, 2011, 10:35:20 AM

I don't see how you find these hard.
I did them in my head. Lol.

Big Brother · November 20, 2011, 10:36:49 AM

got 5/6 on that one, 5 was actually 47 apparently. ty anyway, doesn't bother me lol

nonetheless, moving onward to the final questions..

Chefkokkie · November 20, 2011, 10:37:22 AM

Woops yeah I forgeted that one up.

1st x=109 y=66
2nd x=55 y=60
3rd x=68 y=68
4th x=122 y=74

Tokerovin · November 20, 2011, 10:37:42 AM

This is too easy to ask for help with. My math teacher taught me how to do these in two minutes.

But it's good that your asking for help.

So someone help him.

Big Brother · November 20, 2011, 10:39:51 AM

Quote from: Tokerovin on November 20, 2011, 10:37:42 AM

This is too easy to ask for help with. My math teacher taught me how to do these in two minutes.

But it's good that your asking for help.

So someone help him.

Unfortunately I've never been great in maths, I only partially understand this. Chefkokkie is helping me get through it though, so big thanks to him lol

aludane · November 20, 2011, 10:42:32 AM

Looks like a lot of it is to do with opposite angles or line of angles that cross between eachother.

Big Brother · November 20, 2011, 10:44:13 AM

Quote from: Chefkokkie on November 20, 2011, 10:37:22 AM

Woops yeah I forgeted that one up.

1st x=109 y=66
2nd x=55 y=60
3rd x=68 y=68
4th x=122 y=74

is that going across? like 1 is the top left, 2 is the top right?