okay mr AP prodigy
set up a system like the pic
and measure the force required to pull the string up on the right side
then set up a system with just the right side, none of the left balls
and measure the force required to pull the string up
youd find it to be less.
The forces on the ball in water are B (bouyancy) and W (weight)
B is up and W is down, so net force is B-W
The force on the ball in air is just W going down
to calculate what the net effective force of the system is, put the whole system together and you get (B-W) + W
If (B-W) is greater than W, or vice versa, then the tension of the strings will transfer that to give us a net force of B
This means that the force of gravity due to the ball falling does exist, and is equal to the force of gravity on the one in water.
Both balls cause the system to accelerate, neither resists it or necessarily need to be "pulled along"
You must pull something down if it's being pulled back up.
I think this is a mindforget because of the system's circular nature.
er no you missed the part where I explained how the fluid pressure is where the missing work goes to