Science people: debunk this (OP image fixed)

[Fredulus]

the seal would never work, it's the biggest flaw.

[Ad Bot]

[Kalphiter]

it all could work better if you werent using common stuff.

there are better gasses to have in the balls. and better fluids then just water.

and of course there are no details about how this seal even works lol.

This tends to happen when you try to solve a troll physics problem

[Nexus]

...no? nothing is falling.

:c back to square one

the ball in water accelerates the system by having buoyancy upwards
the ball in air accelerates the system by having a weight downwards <--- Falling :|

[Fredulus]

:c back to square one

the ball in water accelerates the system by having buoyancy upwards
the ball in air accelerates the system by having a weight downwards <--- Falling :|

did you completely ignore my post? the force of gravity on the air ball isn't enough, it still falls slower than the right side is climbing and must be pulled to equalize the speed of both sides.

the force of gravity is about -10m/s2 at sea level

let's say buoyancy adds 30m/s2 to the right side, so that's 20m/s2 of force acting on the right side.
so the left side needs a force of -20m/s2 to keep up with the right side, but it only has -10m/s2 from gravity - thus the right side must "pull" to create that extra -10m/s2 on the left side.

[Nexus]

did you completely ignore my post? the force of gravity on the air ball isn't enough, it still falls slower than the right side is climbing and must be pulled to equalize the speed of both sides.

well first of all I quoted and directly replied to it, and that doesn't change the fact that the ball is falling.  It just so happens that in your scenario it isn't falling fast enough.  In the scenario I replied with, it was falling too fast.  There could be zero tension too if the acceleration of buoyancy was 20m/s.  Then the acceleration of falling would equal acceleration of buoyancy.  In all cases, it is falling.

[Fredulus]

well first of all I quoted and directly replied to it, and that doesn't change the fact that the ball is falling.  It just so happens that in your scenario it isn't falling fast enough.  In the scenario I replied with, it was falling too fast.  There could be zero tension too if the acceleration of buoyancy was 20m/s.  Then the acceleration of falling would equal acceleration of buoyancy.  In all cases, it is falling.

the point from the beginning was the the balls on the left must be pulled. as per my post, they must be pulled. i wouldn't call something being pulled downwards falling.. id call it being pulled downwards. falling is just due to gravity and nothing else.

however you are right that if the force of buoyancy is something like 15m/s2 the left balls will have to pick up the slack. really it depends on what the actual force of the buoyancy would be and i dont want to bother with estimating that as id have to arbitrarily assign sizes to the balls and such.

[Nexus]

Here I think I can explain the conceptual block a bit better now that I understand your argument better:
The falling ball can be dragged by the one floating upwards in some cases.  However, the system would actually still have less acceleration if the falling one wasnt there at all.  The one in water has forces (B-W) and the one in air cancels out the W for a net force of B.  Even though the floating one can be dragging the other ball along because its falling too slowly, the falling one still accelerates the system.  Just because the values in the system cause tensions to change the acceleration that the ball is falling at doesn't change whether it is falling and helping the system.

This is what the trolls were looking for

No they want people to not understand fluids

[dkamm65]

okay I'll explain this mathematically.

the force of gravity is about -10m/s2 at sea level

let's say buoyancy adds 30m/s2 to the right side, so that's 20m/s2 of force acting on the right side.
so the left side needs a force of -20m/s2 to keep up with the right side, but it only has -10m/s2 from gravity - thus the right side must "pull" to create that extra -10m/s2 on the left side.

get it?

and to take this further, youd need to expend even more force to get the balls through the seal, plus relatively small amounts to fight friction - this system is flawed in many many ways.

You're making assumptions about the buoyancy on the right side. Not good when you're using it in an equation to prove a point.

[Fredulus]

under certain circumstances the falling balls will accelerate the system
if acceleration due to buoyancy is greater than 20m/s2 they will be traveling slower than the rest of the system and must be drug along, slowing the overall system down. if buoyancy is less than 20m/s2 they will be advantageous to the system and provide extra acceleration.

You're making assumptions about the buoyancy on the right side. Not good when you're using it in an equation to prove a point.

welcome to like 5 pages ago mr. gravity only acts on one side

[Bisjac]

well if the end goal is to generate power.

then depending on gravity and the buoyancy of water to begin with is already a fail.

all the moving parts needed will not gain enough torque for its own weight.

[Nexus]

under certain circumstances the falling balls will accelerate the system

Under all circumstances, actually.  I suspected that was your conceptual block if you read my post a bit above.

[dkamm65]

welcome to like 5 pages ago mr. gravity only acts on one side

It's still relevant, Mr. I already told you what I actually meant but you can't get it through your skull.

And apparently the previous page is 5 pages ago.

[Fredulus]

Under all circumstances, actually.  I suspected that was your conceptual block if you read my post a bit above.

no. if acceleration due to buoyancy is greater than 20m/s2 force must be expended to drag those balls. force that could have been used to accelerate the rising balls.

[TeslaCoil]

How about "it just won't work and it's clearly obvious?"

You guys have blown this way out of proportion lol.

[Fredulus]

How about "it just won't work and it's clearly obvious?"
You guys have blown this way out of proportion lol.

true that