Author Topic: Algebra help.  (Read 1499 times)


How would I go about solving this?


x y and z are all 1
o_o
you just loving blew my mind
guess I'll figure out how to actually solve it later


at first i was really confused but then i sort of understand it

x y and z are all 1
I think if that were true all the variables would just be called x. Unless it's a trick question and you're school is trying to make you fail.

I think if that were true all the variables would just be called x. Unless it's a trick question and you're school is trying to make you fail.

simplest answer, proven correct by all the problems

turn it into a system of two variables, two equations

I think if that were true all the variables would just be called x. Unless it's a trick question and you're school is trying to make you fail.

never go full handicap

You line them up and subtract. Let me try to remember.

x+2y+z=4
4y+3z=1

so you multiply the first one by 2 to get rid of y first.

2x+4y+2z=4
4y+3z=1
x+-1z=3

Then you repeat except to get rid of Z, but using 3 instead of 2 so that the 3zs line up. Use the product of the last one in that one. Then repeat again with the third equation to finish.

You line them up and subtract. Let me try to remember.

x+2y+z=4
4y+3z=1

so you multiply the first one by 2 to get rid of y first.

2x+4y+2z=4
4y+3z=1
x+-1z=3

Then you repeat except to get rid of Z, but using 3 instead of 2 so that the 3zs line up. Use the product of the last one in that one. Then repeat again with the third equation to finish.
<3

This was an easy problem, lol

just use the substitution property after isolating the variables.

just use the substitution property after isolating the variables.
it was just hard to isolate them for me
but thanks

what grade are you in...?