Better yet, how do i do these problems because im almost guaranteed to get forgeted by this on a future test if i dont learn this.
Backward/reverse solving.
When you have an equation you work on it piece by piece backwards, you do the same to both sides of the '=' sign, this includes reversing BIMDAS/BIDMAS so that + and - come before multiplications and dividers.
This means you work in reverse of the equation to find the original starting factor (x)
e.g. 9(x-8)+3=-15
Start by getting rid of the brackets so you have a simple equation.
9x-72 + 3 = -15
Now we work backwards to get rid of that +3, to do so we take 3 away from both sides, so we get
9x - 72 (the +3 is now gone) = -15 -3 (remember that whatever you do on one side you do to both, making this -18)
Now to get rid of the -72, we add +72 to both sides
9x (72 is eliminated) = -18 + 72 (54)
Now all we have is 9x=54
For the final step, 9x is saying it is x multiplied by 9, to work backwards we divide both the 9x and the 54 by 9 so we get
x=6
Wow I really have nothing better to do with my time, do I? Oh well, these types of equations are without a doubt the easiest to learn, you will pre much have a 100% chance of getting them all right on a test once you understand to just do the entire equation in reverse.
