EDIT: Okay, this is good, this is very good.
We know that either 2 or 3 is in the correct place, and since both results were the same but the last 3 digits were all different, that means the other of the two don't even exist in the code at all. We can kill two digits with one guess here.
uh no it doesn't mean that
a 0 or that 1 could be in the right place, because we removed the 4s and that second 3.
though prove me wrong, i don't see much coming out of this. ill just spectate this for a few guesses.