Poll

What should round 2 be?

4 digits of decimal (Easy)
0 (0%)
4 digits of hexadecimal (Medium)
1 (12.5%)
5 digits of decimal (Hard)
4 (50%)
5 digits of hexadecimal (Insane)
3 (37.5%)

Total Members Voted: 8

Author Topic: Break the Code / Mastermind - Round 2, 5 digits!  (Read 4138 times)


Position 1: 1 2 3 4 6 7 8 9
Position 2: 2 3 4 5 7 8 9
Position 3: 0 3 4 5 6 8 9
Position 4: 0 2 4 5 6 7 9
Position 5: 0 1 3 5 6 7 8

Updated possible numbers list. All we really have to do is whittle this down until we have the right positions, I mean seriously it isn't that hard to understand

Try 12043
I see your strategy, but that's much more useful later in the game. At the beginning, you just need to find what numbers are doubled and stuff like that. For now, let's keep doing doubles like FancyPants was doing, and once we finish with that we can use this.
That is not what I meant to guess. I wanted to write 00123, but oh well.

We now know that 0, 1, and 2 cannot coexist, at least.

NO. DON'T!
It's what FancyPants wrote because yours was 4 digits. Also, his strategy is ok.

Oh my god what is the issue? -.-

The code you listed had both 0, 1, and 2, which guess #3 disproved the possibility of.

It said that only one of those numbers could be there, and I did not put it in the right position. If it had 3 or more slashes, I wouldn't object, but that one slash disproves your guess from the get-go.

I mean I guess I can see why you would do it, but this early in the game it would be distracting.

The code you listed had both 0, 1, and 2, which guess #3 disproved the possibility of.

It said that only one of those numbers could be there, and I did not put it in the right position. If it had 3 or more slashes, I wouldn't object, but that one slash disproves your guess from the get-go.

I mean I guess I can see why you would do it, but this early in the game it would be distracting.
All the slashes mean is that you got nothing in the right place, so we can eliminate the numbers you picked from the positions you picked them in. My method figures out which numbers are not in the right places through elimination, it is not flawed in any way.

All the slashes mean is that you got nothing in the right place, so we can eliminate the numbers you picked from the positions you picked them in. My method figures out which numbers are not in the right places through elimination, it is not flawed in any way.
I mean I guess I can see why you would do it, but this early in the game it would be distracting.
I see your strategy, but that's much more useful later in the game.

All the slashes mean is that you got nothing in the right place, so we can eliminate the numbers you picked from the positions you picked them in. My method figures out which numbers are not in the right places through elimination, it is not flawed in any way.

Fine, do it, but I assure you that we could learn more from a different guess. :K

welp what we got was exactly what i didn't want lol

i think 23344 is a better bet for the next try
[/] [/] [/] [ ] [ ] = either 2 and 3 and 4, 3 is repeated, 4 is repeated, 3 and 4, 4 and 2, or 2 and 3 (holy stuff please dont be this one)
[/] [/] [ ] [ ] [ ] = either 3 is repeated, 4 is repeated, 3 and 4, 4 and 2, or 2 and 3 (don't be this one)
[/] [ ] [ ] [ ] [ ] = either 3 and 4, 4 and 2, or 2 and 3 (yeah sure you should be this one)

it can't be nothing because we know that there's either a 0, 1 or 2, somewhere in the answer.

All the slashes mean is that you got nothing in the right place, so we can eliminate the numbers you picked from the positions you picked them in. My method figures out which numbers are not in the right places through elimination, it is not flawed in any way.
yeah, what you're going for is directly for the Xs, while what im aiming at is simply knowing what's included.

Fine, do it, but I assure you that we could learn more from a different guess. :K
Well since 0 1 and 2 cannot coexist, how about we combine methods and try to eliminate a number from all of them? Try 00134.

EDIT: nope

« Last Edit: October 03, 2013, 10:00:47 PM by Ipquarx »


[X][ ][ ][ ][ ]
______________________
| 17 guesses remain. |
|  Enter code: 23344 |
——————————————————————
:/

EDIT: Realized a mistake.
« Last Edit: October 03, 2013, 10:08:33 PM by TristanLuigi »

So from what I understand, one of the first 4 numbers are in the right place.

So let's try 23001

yikes
well
okay this probably means that three of the digits in the answer are between 0-4, that's pretty likely
i'm going to consider the X a / for the time being until we know for sure what each is
and we need to know by guess 12 or it'll get way too close by the end

So from what I understand, one of the first 4 numbers are in the right place.

So let's try 23001
you're throwing numbers out a little rapidly, though that is an alright method, it relies on a little bit of luck
if we get a lot of slashes that's fantastic
if we get pretty much none that's okay in some cases
if we get two slashes or an X and a slash then it wasn't much help


[X][/][ ][ ][ ]
______________________
| 17 guesses remain. |
|  Enter code: 23344 |
——————————————————————
:/

EDIT: Realized a mistake.

This is terrible. Absolutely terrible.

I should note that our priority always lies in finding which numbers are used, rather than placement. We have to try something totally new and fresh.
« Last Edit: October 03, 2013, 10:07:43 PM by childofdarkness016 »

Sorry I've inflicted so much pain and confusion :P
So are we going with Ipquarx's guess?
EDIT: He's been getting ignored so I will.

[X][/][ ][ ][ ]
______________________
| 16 guesses remain. |
|  Enter code: 23001 |
——————————————————————

if we get a lot of slashes that's fantastic
if we get pretty much none that's okay in some cases
if we get two slashes or an X and a slash then it wasn't much help
I'm trying to narrow down which digit the X is for. By changing two of the four possible digits, that will halve the number of possibilities. And I realize that most of the digits are 0-4, so I included only those. If you have a better suggestion go ahead but I still think it's best to get the correct digit locked in at the same time.

EDIT: Okay, this is good, this is very good.
We know that either 2 or 3 is in the correct place-- So based on the last two, if 2 is in the correct spot, then 3 does not exist in the code. If 3 is in the correct spot, then 2 does not exist in the code. 0 or 1 for sure exists in the code, but not both.
« Last Edit: October 03, 2013, 10:13:12 PM by Ipquarx »

Holy stuff guys, I'm so sorry. I got the 3rd guess's indicators wrong (so when there were 17 guesses left), it's only [X][ ][ ][ ][ ]. I'll give you a free guess back.
Granted, it really didn't change much.