Poll

What should round 2 be?

4 digits of decimal (Easy)
0 (0%)
4 digits of hexadecimal (Medium)
1 (12.5%)
5 digits of decimal (Hard)
4 (50%)
5 digits of hexadecimal (Insane)
3 (37.5%)

Total Members Voted: 8

Author Topic: Break the Code / Mastermind - Round 2, 5 digits!  (Read 4158 times)

i managed it in 7 once, just got lucky at the start.
practiced four or five times after seeing this thread
but uh
five variables
yeah um
uh
well
er

EDIT: What if I increase the code length after every round?
i missssssssed thiiissss

Okay, I'm going to start a poll.
4 digits of decimal has 10,000 combinations and is the easiest.
4 digits of hexadecimal has 65,536 and thus is of medium difficulty.
5 digits of decimal has 100,000 combinations and will be hard.
5 digits of hexadecimal has a whopping 1,048,576 combinations and you will most likely lose.
« Last Edit: October 03, 2013, 09:18:36 PM by TristanLuigi »

Two of the numbers from 0-4 are in the code. Assuming there are no repeats in the code (which there might be) that means 3 are in 5-9

Enter code 56789

Don't be a sore loser. I'm smarter than you and that's what counts~
Umm...
I was not being a sore loser, and let's not forget about Fancy pants, and you.

I'm smarter than you and that's what counts~
 I'm not that great, it seems.
You counteracted your own sentence.

So um...



[/][/][ ][ ][ ]
______________________
| 18 guesses remain. |
|  Enter code: 56789 |
——————————————————————

Ooooooooooooh stuff!!!

There is most definitely a double in there.

start random guessing now.

I'll try 0012.

Ooooooooooooh stuff!!!

There is most definitely a double in there.

start random guessing now.

I'll try 0012.
can you count

There's a repeat of some number in the code, that's all it means.

Here's a list of the possible numbers for each position in the code:
Position 1: 1 2 3 4 6 7 8 9
Position 2: 0 2 3 4 5 7 8 9
Position 3: 0 1 3 4 5 6 8 9
Position 4: 0 1 2 4 5 6 7 9
Position 5: 0 1 2 3 5 6 7 8

So, enter code... 10325

There's a repeat of some number in the code, that's all it means.

Here's a list of the possible numbers for each position in the code:
Position 1: 1 2 3 4 6 7 8 9
Position 2: 0 2 3 4 5 7 8 9
Position 3: 0 1 3 4 5 6 8 9
Position 4: 0 1 2 4 5 6 7 9
Position 5: 0 1 2 3 5 6 7 8

So, enter code... 10325
Order of the indicators doesn't matter.

Order of the indicators doesn't matter.
We tried all numbers, 0-9, and there were only 4 slashes. That means that one of the digits occurs twice.

this isn't even remotely a viable method of finding out numbers waaaaugh

what we know is that two-three of the digits are 0-4 and two-three of the digits are 5-9, that isn't even a little helpful

let's work only with 01234 and see if we can find which of those five are the two numbers we're interested in. i think we can do that in two guesses.

try 00112
it's risky but i think using some doubles is a good idea
if we get [/] [/] [/] [ ] [ ] it will mean either 0 or 1 is repeated
if we get [/] [/] [ ] [ ] [ ] it will mean either 0 or 1 is repeated OR it'll mean 0 and 1 or 1 and 2 or 2 and 0 are in the answer.
if we get [/] [ ] [ ] [ ] [ ] then we'll test 2, 3 and 4 next.
if we get [ ] [ ] [ ] [ ] [ ] then we know 0, 1, or 2 is not in the number and that's fantastic.

We tried all numbers, 0-9, and there were only 4 slashes. That means that one of the digits occurs twice.
That contributed absolutely nothing because it had no doubles in it
let's work only with 01234 and see if we can find which of those five are the two numbers we're interested in. i think we can do that in two guesses.

[/][ ][ ][ ][ ]
______________________
| 17 guesses remain. |
|  Enter code: 00112 |
——————————————————————

christ guys, i've played this with my dad before and he basically came up with a strategy that guarantees a win in less than 18 moves, for codes 6x in length

the trick is to basically bust the first 5 chances doing the following
111222
333444
555666
777888
999000

Using the data from that you will know exactly what numbers are left and how many of each. And usually you'll get at least one on-the-spot hit, but not always.
Since it would kill the fun of the game to give you guys exactly how to do it i'll just leave that here for you guys to figure out.

extrapolate that for 4x and 5x lengths and it'll work. use only TWO different numbers per guess so you know exactly what is and isn't there.
« Last Edit: October 03, 2013, 09:40:44 PM by Conan »

Position 1: 1 2 3 4 6 7 8 9
Position 2: 2 3 4 5 7 8 9
Position 3: 0 3 4 5 6 8 9
Position 4: 0 2 4 5 6 7 9
Position 5: 0 1 3 5 6 7 8

Updated possible numbers list. All we really have to do is whittle this down until we have the right positions, I mean seriously it isn't that hard to understand

Try 12043

That contributed absolutely nothing because it had no doubles in it

[/][ ][ ][ ][ ]
______________________
| 17 guesses remain. |
|  Enter code: 00112 |
——————————————————————

That is not what I meant to guess. I wanted to write 00123, but oh well.

We now know that 0, 1, and 2 cannot coexist, at least.

Position 1: 1 2 3 4 6 7 8 9
Position 2: 2 3 4 5 7 8 9
Position 3: 0 3 4 5 6 8 9
Position 4: 0 2 4 5 6 7 9
Position 5: 0 1 3 5 6 7 8

Updated possible numbers list. All we really have to do is whittle this down until we have the right positions, I mean seriously it isn't that hard to understand

Try 12043

NO. DON'T!