Author Topic: Help poor Swat 3 with his Science homework.  (Read 1460 times)

I really have no idea how to do this. This is a challenge problem that we have to do:

Challenge Question

Little Red Riding Hood, in order to make it to Grandma's house and back home in time for her piano lesson, needs to average 4 mph for the 8-mile trip (4 miles each way). If Little Red Riding Hood goes 2 mph on the way to her Grandma's house, how fast does she need to go on the way back to make it home in time for her lesson?

Yeah so guys if you can figure this out and explain how you got the answer, I will love you.


6 mph

trust me i'm a friend


Depends on how long she's at grandma's house

needs to average 4 mph on an 8 mile trip --> needs to do the whole trip in 2 hours
goes 2 mph on the way there --> 4 / 2 = 2 hours

wtf

6 mph

trust me i'm a friend
no that's wrong

Depends on how long she's at grandma's house
Why would our teacher make us guess.

That isn't the concern of the problem I think.

needs to average 4 mph on an 8 mile trip --> needs to do the whole trip in 2 hours
goes 2 mph on the way there --> 4 / 2 = 2 hours

wtf
i know that is forgeted up ;-;

we are in physics right now
This is math, because you're using scalars.

The answer is simple, don't visit grandma.

we are in physics right now

...that doesn't look like a physics question

to everyone saying it's not physics

it's talking about velocity and motion
it's physics

now, that's not to say it's COMPLICATED physics, but this is probably in one of those 8th or 7th grade "intro-to-physics" classes

d = v*t
d/v = t
8/4 = 2 hours

d = v*t
v = d/t
v = 8/2
v = 4

4 mph, there fixed

Why would our teacher make us guess.
I got it
She would need to teleport back to be on time for piano lessons

let me explain
If she needs to go average 4 mph for 8 miles, she has 2 hours
If she only goes 2 MPH on the way over, and its 4 miles each way, it took 2 hours to get to grandma's.
Therefore, by the time she gets there, she is already late.
« Last Edit: December 15, 2013, 03:32:23 PM by ßlöükfáce »

d = v*t
d/v = t
8/4 = 2 hours

d = v*t
v = d/t
v = 8/2
v = 4

4 mph, there fixed
Do you mean v as speed, because if v is velocity we don't know her direction.

d = v*t
d/v = t
8/4 = 2 hours

d = v*t
v = d/t
v = 8/2
v = 4

4 mph, there fixed
still not right
if she goes 4 miles / hour on the way back she'll get back in 1 hour and her avg speed will be
d=r*t
8=r*3
r=8/3


again there's no solution to this problem because if she wants to average 4 miles an hour on an 8 mile trip she's gonna need to haul more ass on the way there than 2 mph