pythagorean theorem

[bloodnight]

note: your solving B
Can you Figure it out?
Post back with

Code: [Select]

a=# b=# c=#Keep the Post the formula as well.

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[Digmaster]

lol wrong therom.

This looks more trig, silly person.

[Nightmare-Duckie]

i need side B or C

[bloodnight]

i need side B or C

B

@@Digmaster
Its a right triangle...

[Nightmare-Duckie]

        |\
        | \
        |  \
b      |   \  C
17    |    \
        |_    \
        |_|__\
      a
      8 in.
my answer-> C= 18.8 (thats rounded)

[bloodnight]

       |\
        | \
        |  \
b      |   \  C
17    |    \
        |_    \
        |_|__\
      a
      8 in.
C=

You did it wrong...
Lets go over it.
c=16
a=8
C² = a² + b²
16² = 8² + b²
256 = 64 + b²
256- 64= 192
b²= 192
SqrRoot of 192= 13.85
Therefore

Code: [Select]

a=8 b=13.85 c=16

[Nightmare-Duckie]

i'm pretty sure your ahead of me in math because i don't know how to do the only one side stuff
damn i didn't think that through, i see what i did wrong
i got 13.85 when i redid it the right way

[bloodnight]

I'm in 10th grade... =D

you take a and + itself
thats how you get C
then follow the above :)

[Nightmare-Duckie]

:O i'm only in 7th

[Nightmare-Duckie]

    | \
    |  \
    |   \
    |    \   
B  |     \ C
12|      \
in |       \
    |_      \
    |_|___\
       A
       6 in
Sovle For C
(this should be really easy)

[bloodnight]

    | \
    |  \
    |   \
    |    \   
B  |     \ C
12|      \
in |       \
    |_      \
    |_|___\
       A
       6 in
Sovle For C
(this should be really easy)

C= 12

%%%Edit

First post updated

I changed it around

[Antallion]

Ooh, Trig. pfft.

[Nightmare-Duckie]

update is alot cleaner looking :3

[bloodnight]

update is alot cleaner looking :3

I changed the problem again, See if you can do it

Brb shower

[Nightmare-Duckie]

update-> B=23.38
i'm pretty sure i got this one