Poll

Is a circle a polygon? WHILE CIRCLE HAS INFINITE SIDES.

Yes. Because I can see that your mathematical evidence, and the evidence provided by other people, proves it.
No. Because I looked at all the mathematical proof and have determined that in no plausible way is a circle a polygon.
HOW TO MATHS? Choose this option if you're a huge forgettard.

Author Topic: Mathematical Question || Is a Circle a Polygon?  (Read 10679 times)

Polygons have a finite number of sides.

In being infinite, it is also finite.

Abstract mathematics.

Assume there is no mathematical difference between 0.(9) and 1.

Our first problem is that if A = B, then B does not exist, there is only A. But simply by bringing it up, you claim it exists.

A car is traveling down the highway and its speed is equal to A, and A = 30 mi/h.

A van is traveling down the highway and its speed is equal to B, and B = 30 mi/h.

A = B

Our second problem is that if you can assume that an infinite string of the maximum-digit-value numbers brings it up to the next value, then one could say that 9999999 repeating is equal to infinity. If by simply repeating numbers of maximum-digit-value you can get infinity, then all numbers are infinity as long as the system is based on them+1. With a base 2 system 11111111 repeating is infinity. With an extremely odd number system, Pi could be infinity.

In order for 0.(9) to equal 1, all numbers (no matter how small) must be equal to infinity when repeated (including 0.9), and 0.(9) cannot exist.

Totally works.

Actually if you had 9999999.999... (repeating) it would be equal to 10000000. まほ~

Thinking about infinity makes my head literally hurt.

A car is traveling down the highway and its speed is equal to A, and A = 30 mi/h.

A van is traveling down the highway and its speed is equal to B, and B = 30 mi/h.

A = B

Actually if you had 9999999.999... (repeating) it would be equal to 10000000. まほ~

Part one, they are both A, now that A=B.

And not 999999.9999, no decimal. Repeating nines.

I was taught that a polygon is a closed figure with only straight side, and this shows only that the areas of both a circle and a regular polygon can be found in the same way.

Circle still isn't a polygon.


this shows only that the areas of both a circle and a regular polygon can be found in the same way.
there
this
this is what I was trying to say
This is all you "proved"

Also, as you have already previously acknowledged, something is defined by what it is not. Therefore things that are the same, are one and the same. If A is equal to B, then B can be defined by A. Only if B can be defined as not A, can B be defined, where you have only A and B. For the sakes of just A and B, if A=B, there is only one, and that is A or B.

ITT: people who think they're mathematicians, but aren't very good at math at all

ITT: people who think they're mathematicians, but aren't very good at math at all
4 x 1 = 7

Part one, they are both A, now that A=B.


But while B is A, A is B, they both exist as separate entities but with the same value.

And not 999999.9999, no decimal. Repeating nines.

Repeating a number infinitely below 1 does not make it an infinite number.

If you're saying "9999999999..." with an infinite number of 9s without ever going below 1 then firstly, I'm sorry to inform you that mathematics does not work that way, and secondly that that would be equal to infinity because there is no limit to its value. まほ~

1/3 = 0.(3)
1/3 + 1/3 = 0.(6)
0.(6) + 1/3 = 0.(9)

1/3 + 1/3 + 1/3 = (0.(3)) * 3 = 2/3 + 1/3 = 0.(9) = 3/3 = 1

You're wrong.

But while B is A, A is B, they both exist as separate entities but with the same value.

Repeating a number infinitely below 1 does not make it an infinite number.

If you're saying "9999999999..." with an infinite number of 9s without ever going below 1 then firstly, I'm sorry to inform you that mathematics does not work that way, and secondly that that would be equal to infinity because there is no limit to its value. まほ~

Part one, how can they be separate if they are the same.

Also, your second part is lol.

You basically say that after infinity 9's you must reach a decimal, implying that there is a point beyond infinity, which would imply that there is a number in between 0.(9) and 1.

And yes, the point of my argument was to show that everything equals infinity if you round it up at the ininityth point.

1/3 = 0.(3)
1/3 + 1/3 = 0.(6)
0.(6) + 1/3 = 0.(9)

1/3 + 1/3 + 1/3 = (0.(3)) * 3 = 2/3 + 1/3 = 0.(9) = 3/3 = 1

You're wrong.
There is no decimal value for those fractions, those are rounded.

I give up you're a moron.