Author Topic: Math Problems  (Read 6835 times)

If you are really 12, you should have started it already..
pre-algebra*

but this is easy, just wait a year or two and it gets harder.

Yeah, you think this algebra stuff is hard?

Try finding the height of something over forty feet tall with only a ruler and a mirror, to the inch
geometry. NO BIGGIE. gime a problem, brah.
« Last Edit: November 29, 2012, 09:12:11 PM by ultimamax »

prealgebra is loving easy

THIS

IS THE loving stuff WE ARE DOING

X · Y= 144

WHAT THE forget IS THIS stuff
« Last Edit: November 29, 2012, 09:25:13 PM by blockguy123 »


It has to do with graphs, hello.

x and y are both axis's on a graph.

We can say X=72 and y=2.

Therefore, 72*2=144.

Solve:
The area of a circle that has a 2 in. radius.



Just for fun, I'll post this easy one.

Solve:
The area of a circle that has a 2 in. radius.

12.57 in^2

Just to use you as a clue.
« Last Edit: November 29, 2012, 09:42:42 PM by Jerkface »


A car, at 4.4 seconds, travelled 56 kilometers. The car has travelled 128km by 15 seconds. Find the rate of speed at which the car went between the two points and show your work.

It has to do with graphs, hello.

x and y are both axis's on a graph.

We can say X=72 and y=2.

Therefore, 72*2=144.

Solve:
The area of a circle that has a 2 in. radius.
You're dumb. X and Y could be any two corresponding factors of 144, like 12 and 12. Not just those numbers. It is impossible to prove either variable.

The circle's area is 12.5663706144.


A car travels 48 mph for a distance and then 72 mph for that same distance. What is it's average speed.

A car travels 48 mph for a distance and then 72 mph for that same distance. What is it's average speed.
You need to provide the distance. Plus, I already did this.
A car, at 4.4 seconds, travelled 56 kilometers. The car has travelled 128km by 15 seconds. Find the rate of speed at which the car went between the two points and show your work.


You need to provide the distance.
You don't need the distance.

You don't need the distance.
v = d/t
You also provided two different speeds without giving a distance or time, looking more closely.
« Last Edit: November 29, 2012, 09:58:04 PM by PowerDag »

v = d/t
both distances are exactly equal
substitute for value X, which is the distance