Controlling bots with another brick

[ManFlakes]

Is there an addon where I can control a bot from another brick?
For example  OnActivate>Named brick>GoTobrick
                                        Bott hole
I'm modifying beta city like adding more buildings and making it more lively with bots but
the limitations I have now with controlling bots are making me not able to do some scenarios.

[Ad Bot]

[Dannu]

You can do a onfirerelay>events on the bot hole, name the bot hole, make the other brick have onactivate>botholenamedbrick>firerelay

[SgtDaemon]

You can do a onfirerelay>events on the bot hole, name the bot hole, make the other brick have onactivate>botholenamedbrick>firerelay

OnRelay only has Self and Named Brick targets. There is no target for Bot, which is what OP asks for.

[Dannu]

It does on bot holes, or should at least.

[ManFlakes]

Seems too complicated and it looks like I still wouldn't be able to do some things.
But it's the only solution right now.

[Dannu]

No.. It's actually what firerelay was intended for. This is the solution for triggering stuff like this.

[Adolf-kun]

Bott hole

lol am I the only one who didn't miss this

[ManFlakes]

No.. It's actually what firerelay was intended for. This is the solution for triggering stuff like this.

Alright then. I didn't really know because I have never used relays. Never had any use for them.

[ManFlakes]

lol am I the only one who didn't miss this

I was wondering how much time it would take for someone to find it.

[ManFlakes]

No.. It's actually what firerelay was intended for. This is the solution for triggering stuff like this.

So I tried this, and it didn't work. I wanted so when a projectile hits a brick, the bot shoots.
I tried doing what you said, it was like this:
onProjectileHit>Named brick>fireRelay
                         Dikhole
and then on the bot hole I got stuck with:
OnRelay>Self
               Named brick
I can't control the bot like that. Unless I'm missing something and doing it wrong.

[Dannu]

Then i must have been mistaken. Not sure how to approach this then..