Math

[Diargon]

Are they negative numbahs?

[Ad Bot]

[Otis Da HousKat]

I don't really know what a loving intregal is. The point is to find the numbers for x that are between 0 and 1 exclusive.

Find what values of x are between 1 and 0?

Answer: 0<x<1

[Muffinmix]

Yeah I tried deriving it and doing a little algebra work and I'm just going around in circles, I don't get it.

One thing though, when x approaches 1

A(1)2 + B(1) + C = 0
A + B + C = 0, smallest possible positive number

So, you could half ass it and say x=0.9999... and C=0

Then A and B are super small as well, you get the smallest possible number.

So A, B and C approach (or are) 0, X approaches 1 to get the smallest number.

[Ladios]

None of them can be 0.

[Muffinmix]

Oh.

X = 0.999...
A = 0.000...1
B = 0.000...1
C = 0.000...1

Hey it works, I don't know

[Ladios]

But that wouldn't be 0... it would be really loving low, yes, but not 0.

[Muffinmix]

But that wouldn't be 0... it would be really loving low, yes, but not 0.

Oh hmm, yeah

Are you sure A, B and C can't be zero? Or negative?

[Randomguy]

If none of them can be zero, and they all have to be positive, then how is it supposed to equal zero? Am I missing something?

[FlyGuy45]

I do not know, perhaps its an asymptote or something? It seems to be impossible. If it doesn't reach zero then it must be some kind of this?

http://www.freemathhelp.com/asymptotes.html

[Ladios]

Are you sure A, B and C can't be zero? Or negative?

Ineed.
I beleive it all depends on the x really. Maybe some fraction or radical but really I dunno...

[Gamefandan]

Did I win?

[Hugums]

42

Answer to everything

[Mr. Snipe]

lol@gamefandan

[Mateo]

I'm fairly certain it's impossible. 3 positives added together can't make 0.

[Reactor Worker]

Only the coefficients A, B and C have to be positive. X could be 0 or less.

So... if we made it like this..

1(-1)²+2(-1)+1=0

A=1
B=2
C=1

?

Woops, should have read the OP better. :(