Author Topic: Impossible Math  (Read 3917 times)

x = y
x^2 = xy
x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)
x+y = y
2y = y
2 = 1
1 = 0
But, the only number that x can equal is clearly 0.
Damn cancelling of variables.  It's clearly broken.



If it doesn't divide by zero and create a black hole it's not worth solving. :U

x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)

This is where I'm thinking a mistake might be. But it's been a few months since I've done any math :3 (well, other than every day stuff of course)

x^2-y^2 = xy-y^2
(x+y)(x-y) = y(x-y)
Thats obviously messed up.

How2readreallyhardmaththatido ntknow?

I was right :D

There would have had to be a mistake, math doesn't just come up with stuff like 2=1 unless you make a mistake.

How2readreallyhardmaththatidontknow?

You read it by having an education higher than 7th grade.

x+y = y
2y = y


These are possible. In the first one x is zero and y can be anything.

In the second one y is zero.

If both x and y are zero, it works.

If it doesn't divide by zero and create a black hole it's not worth solving. :U


chuck norris can


inb4 divide by zero pics

« Last Edit: July 28, 2009, 10:28:59 PM by tails »