Math Problem (see if you can do it!)

[Scar. z]

Ok here is a question:

  ABXA=CCC

Find out the sum and what each digit is in the problem. Any letter that shows in the Problem more than once must be the same Digit

I just edited, I made a mistake

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[@Ravencroft]

5(4)+5=8.3(8.3)(8.3)

[Scar. z]

5(4)+5=8.3(8.3)(8.3)

Nope the answer has to be like 674

[@Ravencroft]

Nope the answer has to be like 674

joke---->
Your head
 

[Ipquarx]

so do you mean a * b + a = c * c * c
or 10 * a + b + a = 100 * c + 10 * c + c

[Renekar]

http://m.wolframalpha.com/input/?i=674%3Dab%2Ba&x=0&y=0
I am pro

[Char]

a=1, b=0, c=1

1*0+1=1*1*1
0+1=1
1=1

you're probably going to tell me I can't use the same number twice are you

a=2, b=-.5, c=1

2*(-.5)+2=1*1*1
-1+2=1
1=1

you know what I just realized you said the answer has to be 674
why does it?
why didn't you just put that in the OP?

[Scar. z]

a=1, b=0, c=1

1*0+1=1*1*1
0+1=1
1=1

you're probably going to tell me I can't use the same number twice are you

a=2, b=-.5, c=1

2*(-.5)+2=1*1*1
-1+2=1
1=1

you know what I just realized you said the answer has to be 674
why does it?
why didn't you just put that in the OP?

I said that as a Example to show it had to be a normal 3 digit number

[Eden]

So does the B signify A x B or say A is 4 and B is 6 so AB = 46?

[ultimamax]

ab + a = c^3

a = 0 b = 0 c = 0

or

a = 1 b = cube root(c)-1 c = any number

or

a = 1 b = 26 c = 3


Could you give us a math problem that we can solve algebraically? aka with constants?

[Char]

I said that as a Example to show it had to be a normal 3 digit number

okay, so CCC is not C*C*C but the same three numbers repeated, like 222 or something?

also changing * to X is more confusing because you can't tell if it's supposed to be * or another digit...

[Ipquarx]

In that case then the only solution is 0,0,0.

There is no other solution, 99 + 9 is less than 111 and that's the maximum you can get.

[Scar. z]

Damn for when i edited it you could've done 37 X 3= 111

[Gumba Jonny]

setro 2.0 ladies and gentlemen

[Blockguy345]

so
 a × b × x × a= c × c × c
correct