Author Topic: Algebra II Help? Square Roots Homework  (Read 2551 times)

We're doing Alg. I review now, and last year, we did this for one day.


This homework is due tomorrow, and I have no idea how to do the rest of the questions (or even some of the ones I completed). Can someone please help me? This is 9th grade Algebra II Honors.

I have trouble with algebra II, or Adv Algebra too

I can help, I'm in algebra 2 too. Give me the problems and I'll see what I can do

I can help, I'm in algebra 2 too. Give me the problems and I'll see what I can do
They're in OP. But I'll write them out

10) -2√8 - √6 - √8 - √6
11) -√20 - √5 + 2√20 - 3√5

I'm working on the rest. But...

3√6 - √54 , I got the answer 0 because √54 = 3√6 and 3√6 - 3√6 =0, right?

Yes you're right, it is equal to zero.

Yes you're right, it is equal to zero.
Excellent! The thing is, I don't know how to do the rest. None of my friends in my class know either. If you could maybe help me? I don't need the answer, I need to try it myself


hm so you want steps
I just got the answer you said anyway

For 11 did you get 0?

I got -2 times square root 5

I got -2 times square root 5
I got it too. Instead of 4√5 I put 6√5 oops

But the distributing one I'm totally confused on

I got it too. Instead of 4√5 I put 6√5 oops

But the distributing one I'm totally confused on
which one is the disturbing one again?

which one is the disturbing one again?
*distributing

Basically 13, 15-17. I'm trying to figure it out

10) -2√8 - √6 - √8 - √6

I'll start with this one.

First we separate the terms:

-2√8 - √8
-√6 - √6

If we do the operations, we get:

-3√8 which equals -3●2√2 or -6√2
-2√6

Since any further simplification will just make more terms, the final answer would be -6√2 - 2√6.

11) -√20 - √5 + 2√20 - 3√5

Same thing for this:

-√20 + 2√20 = √20 = √4√5 = 2√5
-√5 - 3√5 = -4√5

Combine them to get 2√5 - 4√5 and the final answer is -2√5.

I hope I've been some help. I took almost 3 years to get through Algebra I and then passed Algebra 2 with a 98% for the whole year. Granted, it's been long enough to slip up on some things, but if you need more help, I can try.

^ Cubed already helped me with those, but thank you for helping. I have trouble with #13 in OP.

And thank you Cubed Root. You've helped me a lot today :)

For number 13, would you like the steps or the answer?